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Heat required for this transition is given as the the sum of three heats

heat required for heating the ice from -5 degree Celsius +latent heat(conversion of ice at zero degree to water at zero degrees)+heat required to heat the water from 0 to 5 degree Celsius

Heating of ice=m x s x delta T,where m is the mass ,s is the specific heat of ice

=200x0.5x5

=500cal

melting of ice=mxlatent heat

=200x80

=16,000cal

Heating of water=m x s x delta T,where m is the mass ,s is the specific heat of water =200x1x5

=1000cal

Total heat required=500+16,000+1000

=17,500 cal

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Q: How much heat is required to change 0.2kg of ice at -5 degrees to water at 5 degrees?
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