Heat required for this transition is given as the the sum of three heats
heat required for heating the ice from -5 degree Celsius +latent heat(conversion of ice at zero degree to water at zero degrees)+heat required to heat the water from 0 to 5 degree Celsius
Heating of ice=m x s x delta T,where m is the mass ,s is the specific heat of ice
=200x0.5x5
=500cal
melting of ice=mxlatent heat
=200x80
=16,000cal
Heating of water=m x s x delta T,where m is the mass ,s is the specific heat of water =200x1x5
=1000cal
Total heat required=500+16,000+1000
=17,500 cal
there are 1000 g in 1 kg, 20g=.02kg hint, the prefix k means 1000