Density = grams/ml
1.00 g/ml = X g/5.0 ml
= 5.0 grams water
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q(joules) = mass * specific heat * change in temp.
q = (5.0 grams)(4.180 J/gC)(75 C - 2.50 C)
= 1515.25 Joules
---------------------------------/4.184
= 362 calories
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The energy required to raise the temperature 1 degree Celsius of 1 gram of water (1 mL) is 1 calorie (=4.18 J). So for 1 kg, 1Kcal (= 4180 J = 4.18 KJ) is required. To raise it 60 degrees, just multiply by 60 and for 10 kg multiply by 10 again. That would make 2.508 MJ (= 2508000 J) Now this is not completely accurate. The energy required to raise the temperature of water differs at 20 degrees from that at 60 degrees. The difference is small (~0.05 J or something like that) but still present.
That's going to depend on how much water you're responsible for. Teacup at 60 degrees . . . very few BTU. Swimming pool at 60 degrees . . . many more BTU. It's also going to depend on whether you're talking about Celsius or Fahrenheit degrees. Fahrenheit degrees . . . fewer BTU. Celsius degrees . . . more BTU. (Also, the water will escape as you pass 100.) In general, one BTU is approximately the energy required to raise the temperature of 1 pound of water 1 degree Fahrenheit. You can take it from there, when you reach the job site and determine the exact scope of the work.
200 BTU. I'm assuming your temperatures are in Fahrenheit, since all of your other measurements are in the Imperial system. A BTU is defined as the amount of energy required to raise the temperature of 1 pound water by 1 degree F, so the temperature is raised by 20 degrees, and 10 pounds of water: 20 x 10 = 200
Heating of water=m x s x delta T,where m is the mass ,s is the specific heat of water(1 cal/gm)=5x1x(50-25) =125 cal
The specific heat of air at 0 degrees Celsius is 1.01 Joules per gram or J/g. The specific heat of a substance is defined as the quantity of heat per unit mass needed to raise its temperature by one degree Celsius.
3.50 J
1935 J (apex)
15480.80
The number of calories required will depend on the mass of water which is to be heated.
The amount of heat required to increase the temperature of the substance to 1 degree greater than that of the initial temperature of the body!
1935 J (apex)
15.37684 joules
false its 1 degrees Celsius
The energy required to raise the temperature 1 degree Celsius of 1 gram of water (1 mL) is 1 calorie (=4.18 J). So for 1 kg, 1Kcal (= 4180 J = 4.18 KJ) is required. To raise it 60 degrees, just multiply by 60 and for 10 kg multiply by 10 again. That would make 2.508 MJ (= 2508000 J) Now this is not completely accurate. The energy required to raise the temperature of water differs at 20 degrees from that at 60 degrees. The difference is small (~0.05 J or something like that) but still present.
21 Kg = 2100 grams to rise the temperature of this amount of water by 2 degrees Celsius you need 2*2100 = 4200 calories or 17572.8 Joules.
1935
mmmm enthalpy