We must first know the heat of fusion of water, which is the required energy to melt a given quantity of ice. For water, this is 334 J/g. 334 Joules have to be applied to one gram of 32°F ice to melt it, so 334 Joules have to be taken out of one gram of 32°F water to freeze it.
10 pounds is 4,535.9237 grams, so (4,535.9237) * 334 gives us 1,514,998.52, the amount of energy in Joules that has to be removed from 10 pounds of water to freeze it.
The final answer is 1.51499852 MJ (megajoules)
1 BTU is required to raise 1lb of water 1 degree F in 1 hour. 212-75=137 degrees 600 lbs water x 137 degrees= 82,200 BTU's required to change 75 degree water to 212 degree water. To change 212 degree water to 212 degree steam it requires 970 btu's (latent heat of vaporization) per lb of water 970 btu x 600 lbs water = 582,000 btu Answer - 582,000 btu+ 82,200 btu = 664,200 btu's
135 btu
U.S.gallon = 8.33 pounds of water. Therefore to raise the temperature by one degree F will require 8.33 BTU. The initial temperature of 50 F is inconsequential.
1 Degree of Celsius is larger. The number of degrees Fahrenheit between Water freezing (32) and boiling(212) is 180 degrees. The number of degrees Celsius is 100 degrees. So the Celsius degree has more value.
200 BTU. I'm assuming your temperatures are in Fahrenheit, since all of your other measurements are in the Imperial system. A BTU is defined as the amount of energy required to raise the temperature of 1 pound water by 1 degree F, so the temperature is raised by 20 degrees, and 10 pounds of water: 20 x 10 = 200
None. Changing water from 25 degrees C to 5 degrees C requires heat to be REMOVED, not added!
How many degrees water weights 7975 pounds
1 BTU is required to raise 1lb of water 1 degree F in 1 hour. 212-75=137 degrees 600 lbs water x 137 degrees= 82,200 BTU's required to change 75 degree water to 212 degree water. To change 212 degree water to 212 degree steam it requires 970 btu's (latent heat of vaporization) per lb of water 970 btu x 600 lbs water = 582,000 btu Answer - 582,000 btu+ 82,200 btu = 664,200 btu's
135 btu
74,970
You need to remove 1879 Joules.
55 degrees celsius
About, 30 degrees
0 degrees
100 degrees cel.
U.S.gallon = 8.33 pounds of water. Therefore to raise the temperature by one degree F will require 8.33 BTU. The initial temperature of 50 F is inconsequential.
32 degrees Fahrenheit0 degrees Celsius