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How much helium is required to lift an object weighing 210 grams?
Wiki User
∙ 10y ago
lets estimate ... helium weighs 4 g / 22.4 L at stp. Air is about (.8*28 +.2*32) or 28.8 g / 22.4 L at stp. this gives a lifting ability of 28.8-4 = 24.8 g for 4 g of helium.
210 / 24.8 = 8.468 times as much. or 8.468 x 4 = 33.872 g He
or 8.468 x 22.4 = 189.6832 Liters of He at stp.
This ignores any weight of a balloon to hold the helium or a 'basket' to hold the 210 g object. This is about 6.5 or 7 cubic feet of He, a large amount. weight of the balloon will become important.
Wiki User
∙ 10y ago
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