answersLogoWhite

0

lets estimate ... helium weighs 4 g / 22.4 L at stp. Air is about (.8*28 +.2*32) or 28.8 g / 22.4 L at stp. this gives a lifting ability of 28.8-4 = 24.8 g for 4 g of helium.

210 / 24.8 = 8.468 times as much. or 8.468 x 4 = 33.872 g He

or 8.468 x 22.4 = 189.6832 Liters of He at stp.

This ignores any weight of a balloon to hold the helium or a 'basket' to hold the 210 g object. This is about 6.5 or 7 cubic feet of He, a large amount. weight of the balloon will become important.

User Avatar

Wiki User

11y ago

Still curious? Ask our experts.

Chat with our AI personalities

FranFran
I've made my fair share of mistakes, and if I can help you avoid a few, I'd sure like to try.
Chat with Fran
RafaRafa
There's no fun in playing it safe. Why not try something a little unhinged?
Chat with Rafa
SteveSteve
Knowledge is a journey, you know? We'll get there.
Chat with Steve

Add your answer:

Earn +20 pts
Q: How much helium is required to lift an object weighing 210 grams?
Write your answer...
Submit
Still have questions?
magnify glass
imp