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How much helium is required to lift an object weighing 210 grams?
Wiki User
∙ 11y ago
lets estimate ... helium weighs 4 g / 22.4 L at stp. Air is about (.8*28 +.2*32) or 28.8 g / 22.4 L at stp. this gives a lifting ability of 28.8-4 = 24.8 g for 4 g of helium.
210 / 24.8 = 8.468 times as much. or 8.468 x 4 = 33.872 g He
or 8.468 x 22.4 = 189.6832 Liters of He at stp.
This ignores any weight of a balloon to hold the helium or a 'basket' to hold the 210 g object. This is about 6.5 or 7 cubic feet of He, a large amount. weight of the balloon will become important.
Wiki User
∙ 11y ago
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What has more atoms 2.88 grams of helium atoms or 16.4 grams of zinc atoms?
2,88 grams of helium have 3,761.1023 atoms; 16,4 grams of zinc have 1,511.1023 atoms.
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The molar mass of helium is 4 g/mol. This means that 1 mole of helium has a mass of 4 grams. Since 2.5 moles of helium have a mass of 10 grams, the atomic mass of helium is 4 grams/mol.
How many moles in 6.071grams of helium?
To find the number of moles in 6.071 grams of helium, divide the given mass by the molar mass of helium. The molar mass of helium is approximately 4 grams per mole. Therefore, 6.071 grams / 4 grams/mol ≈ 1.52 moles of helium.
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What has more atoms 2.88 grams of helium atoms or 16.4 grams of zinc atoms?
2,88 grams of helium have 3,761.1023 atoms; 16,4 grams of zinc have 1,511.1023 atoms.
What is the atomic mass of helium if you know that 2.5 mo of helium has a mass of 10 grams?
The molar mass of helium is 4 g/mol. This means that 1 mole of helium has a mass of 4 grams. Since 2.5 moles of helium have a mass of 10 grams, the atomic mass of helium is 4 grams/mol.
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How many moles in 6.071grams of helium?
To find the number of moles in 6.071 grams of helium, divide the given mass by the molar mass of helium. The molar mass of helium is approximately 4 grams per mole. Therefore, 6.071 grams / 4 grams/mol ≈ 1.52 moles of helium.
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