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The net output of useful work is (weight) times (gain in height) = 2,000 newton-meters = 2,000 joules.

The rate of doing the work, and adding to his gravitational potential energy,

is (2,000/40) = 50 joules per second = 50 watts.

He certainly had to generate and expend more power than that in order to accomplish the climb.

But most of the energy he expended went into heating his muscles and the rest of his body.

50 watts is the power that went into the useful part of hoisting his weight to a position of five

meters higher than where he started.

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Q: How much power is applied if a person weighing 400 newtons climbs a five meter pole in 40 seconds?
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