You need to make your question clearer.
.47 watt
To lift a 950-N load 3 meters requires (950 x 3) = 2,850 joules of energy.The power is the rate at which the energy is delivered. It takes more powerto lift the load faster.The power used to lift this load is (2,850 joules) divided by (the number of seconds it takes),and the unit of the answer is watts.
Some seconds (1 minute/60 seconds)
Although most of the time power is measured in Watts, it can also be expressed as Js-1. So in your question, you are given the amount of joules and the time in hours. First, convert 5 hours to seconds. There are 60 mins in an hour and 60 seconds in a minute. So that's going to be 5x60x60 = 18000 seconds Now all you do in divide the number of joules by the number of seconds to work out the power. So that's 7500/18000 = 0.41666666666... approximately, 0.42Js-1(2dp) and thats the same as 0.42W (2dp)
Use the definition of power as energy / time. Or work / time; it's basically the same thing.
do not hnow
If work or energy was exerted or transferred in 2 seconds,then the power was(1/2) x (the number of joules of work or energy) watts.
27,000 J
.47 watt
Power = (energy used) / (time to use that much energy) = 40/5 = 8 watts
3000
15 KJ
25 newtons
Power=(Force X distance) / (time) P= (13N x 3m) / (5 sec) P= 7.8 Watts
Power = energy/time During those 25 seconds, the machine is doing work at the rate of 800/25 = 32 watts. We don't know how much power the machine must consume in order to perform work at that rate, but we know it's more than 32 watts.
6000 joules / 70 seconds = 85.71 watts
An energy meter measures power and time; a wattmeter measures an instantaneous value of power. Energy = Watt/seconds.