12" x 12" x 1" = 144 cubic inches = 1/12 of a cubic foot.
I think 80-95 pounds i did a little research on it
1/12 of a foot is in 1in.
I am 12. I am 5"2'. I weigh 107. Hope this helps
it depends on the grades of sand and how big each pebble is that makes sand.
The answer will depend on the units for 2. Whether it is 2 inches, feet or something else. Assuming you mean feet, a 12 foot x 12 foot x 2 foot area contains 288 cubic feet. Sand is usually measured in lbs. One cubic foot of sand weighs about 100 lbs (see related questions below). 288 x 100 lbs = 28800 lbs. This is 14.4 tons of sand.
To calculate the volume of sand needed to cover an 8x16 area at 1 inch thick, first convert the dimensions to feet: 8 feet by 16 feet. The area is 128 square feet. Since 1 inch is 1/12 of a foot, the volume of sand required is 128 square feet multiplied by 1/12 foot, which equals approximately 10.67 cubic feet of sand.
do it yourself 1in = 2.2 cm 12 in = 1ft
1in = 0.0254m (exactly) ⇒ 12in = 0.3048m
It is (151*12)+1 = 1813 inches
2.54cm = 1in 1cm = 1/2.54in 175.5cm = 175.5 / 2.54 in ~= 69 in 12 in = 1 ft 1in = 1/12ft 69in = 69/12 ft = 5 9/12 ft = 5 ft 9in
151(12)+1=1813 1813
The area that 40 pounds of sand will cover at a depth of 1 inch can be estimated based on the density of sand, which is typically around 100 pounds per cubic foot. Since 40 pounds of sand is about 0.4 cubic feet, and 1 inch is ( \frac{1}{12} ) of a foot, the area covered would be approximately 4.8 square feet. Therefore, 40 pounds of sand will cover roughly 4.8 square feet at a depth of 1 inch.