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Q: If a digital combination lock on a phone has 4 spaces with digits 0 to 9. How many 4 digit combination lock codes are possible?

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I would have to say 10,000 possible combinations. (0000, 0001, 0002 through 9998, 9999)

Designing Spaces - 2005 ATandT Home Digital was released on: USA: February 2013

Yes. Names can contain letters, digits, and spaces, as well as most of the punctuation symbols.

letters, digits, special characters and white spaces

There are nine numbers which contain only one digit. There are 90 numbers which contain two digits. There are 900 numbers which contain three digits. There is one number which contains four digits.Therefore, the number of digits is equal to (9x1)+(90x2)+(900x3)+4 = 2893 digits. If this includes spaces, there would be 999 spaces, therefore there would be 3892 keystrokes.

Try and you'll thank me, remove the spaces cutt .ly/onPS1UE

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In some condos this is possible, and most do have spaces. However some do not. Its best to ask to see what an agreement entails.

there are bookcases that are made for all sizes of spaces make sure to take accurate measurements to get the best results possible.

The general formula is to square the number of digits it could be (in this case 5) by how many spaces there are. So in this case it would be 53 = 125 possible combinations.

Digital Products are products that is not in physical or intangible, these are the products that can be downloaded over the internet. Examples of digital products are PDF, eBooks, software, movie, plugins, mobile apps, etc.

The best guess is probably 14 numeric digits but when written down with the + () - spaces and other characters about 21 works.

1.Letters 2.Digits 3.Special characters 4.White spaces

For only the digits: 5,888,896. More if there are commas as thousands separators (as in this answer), or spaces between numbers (999,999 of those).

You count every character and all the spaces, then multiply it by 8. Each character and space is represented in 8 binary digits which are called bits BInary digiTS. 8 bits make a byte and 1 byte represents a single character or space. So, when you count the characters and spaces in a sentence, you will know the number of bytes the sentence has. So, multiply that number by 8 and you will know how many bits.

Zone of saturation

Zone of aeration

Zone of saturation

The decimal point is positioned between the digits whose place value is units (10^0) and tenths (10^-1). To the left of the decimal point, the digits may be grouped in threes by using commas or spaces eg 12 345 678.923 or 12,345,678.923

This is actually very simple: convert each octal digit to a group of 3 binary digits. Example: 453 (octal) = 010 101 011 (binary). You would normally leave out the spaces between the digits; I only put them there to emphasize that each group of three binary digits came from a single octal digit.

In representing large numbers, English texts use commas (or spaces) to separate each group of three digits. This is almost always done for numbers of six or more digits, and optionally for five (or even four) digits. This makes it easier to read the number without having to count how many place holders there are in the number as a whole.

I always use two spaces because that is how I was taught many years ago, but WikiAnswers always shortens it to one space when I send my answer. See? They just did it again. I think two spaces helps to separate the sentences, but perhaps it is no longer observed anymore, and one space is considered enough in the Digital Age.

False.

2 spaces!

The spaces between cells are pores or air spaces. These spaces are scientifically called intercellular or extracellular spaces or material.