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How much time is required for a 5.75 mg sample of Cr-51 to decay to 1.44 mg if it has a half life of 27.8 days?
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How many days rest required after circumstance operation?
15 days
What fraction of a radium sample will remain after 3240?
The answer depends on 3240 WHAT: seconds, days, years?
17 weeks is equal to how many days?
1 week = 7 days. You now have all the information required to answer this and similar questions.
96 men in 24 days does a job. How many people required to do the same job in 20 days?
96 x 24/20 = 116 for first 4 days and 115 for remaining 16 days
How can you calculate BOD Mathmaticly?
The Biochemical Oxygen Demand (BOD) of a sample is the amount of dissolved oxygen required by aerobic microorganisms to breakdown organic matter in the sample.The test is simple:Measure the Dissolved Oxygen content of the sample (a)Place in a sealed darkened bottleIncubate for 5 days at 20'CMeasure the Dissolved Oxygen content of the incubated sample (b)Generally you're using this test to analyse contaminated water, so you'll want to dilute it first - it may be that aren't enough aerobic microorganisms present to give you a measurable result, in which case you'll need to inoculate the sample with a suitable culture.The BOD of the sample = a - bBOD is expressed in mg O2/L of sample.Extra CreditGenerally you're using this test to analyse contaminated water, so you'll want to dilute it first - it may be that aren't enough aerobic microorganisms present to give you a measurable result, in which case you'll need to inoculate the sample with a suitable culture.The BOD of a diluted innoculated sample = ((a - b) - BOD of inoculated culture) * dilution factor
How many days must elapse for a 0.80 Mg sample of iodine-131 in the thyroid to decay to 0.10 Mg?
The time required is 24.06 days. The half life of iodine 131 is 8.02 days.
How long does it take a 100.00g sample of Au-1.98 to decay to 6.25g?
10.76 days
How much time is required for a 6.95 sample of to decay to 0.850 if it has a half-life of 27.8 days?
The time required for a 6.95 sample to decay to 0.850 if it has a half-life of 27.8 days is 255 days/ Radioactive decay is based on half-lifes, specifically the reciprocols of powers of 2. The equation for decay is... AN = A0 2(-N/H), where A is activity, N is number of half lives, and H is half life. Calculating for the question at hand... 0.850 = 6.95 2(-N/27.8) 0.122 = 2(-N/27.8) log2(0.122) = -N/27.8 -3.04 = -N/27.8 N = 9.16, or TN = (9.16) (27.8) = 255
How many days are required for 200 grams of radon-222 to decay to 50.0 grams?
7.64 days
What is the half life of a radioactive isotope if it takes 6.2 days for a 72 gram sample to decay to 18grams?
18 grams are one fourth of the original sample mass of 72 grams. Accordingly, the half life is 6.2/4 = 1.55 days.
How long will it take for a 12.0-g sample of iodine-131 to decay to leave a total of 1.50 g of the isotope The half-life of iodine-131 is 8.07 days?
half life is 8.1 days, so it takes 8.1 days for half the iodine sample to decay. It takes another 8.1 days for half of the remaining sample (ie. 1/4th of the original sample) to decay. So it takes 16.2 days for 3/4th of the sample to decay.
How many days are required for 200 grams of radon-222 to decay to 50 grams?
7.64 it is the half life of radon-222 multipled by 2
What is the half life of radioisotope?
Half life is the time taken for approximately half of the available nuclei in a sample of radioactive material to decay into something else. It's a characteristic of the isotope, for example, the half life of the isotope of iodine, I131 is 8.08 days. Half lives can vary from fractions of a second to thousands of years.
How many days are required for 200 grams of radon 222 to decay to 50.0 grams?
7.64 it is the half life of radon-222 multipled by 2
The half life of iodine-131 is 8.0252 days How long will it take for a sample to decay to three-fourths of its original size?
A radioactive nuclide with a half-life of 8.0252 days will decay to 0.75 of its original size in 3.33 days. AT = A0 2(-T/H) 0.75 = (1) 2(-T/8.0252) log2(0.75) = log2(2(-T/8.0252)) -0.415 = -T/8.0252 T = 3.33
Will a sample of radon-222 eventually all disappear?
Maybe, and maybe not. It depends on how large the sample is and how long "eventually" is. Though radon has a modest half-life, it still takes a long, long time for any appreciable amount to decay to the point where we can't detect it. Remember that any "sample" will contain radon atoms numbered in many powers of ten. Then there's the fact that a half-life is a statistically derived amount of time, meaning that a single given atom or a small number of atoms won't "obey" the "rule" of the half-life and decay "on schedule" per the time cited. All the atoms of radon-222 may not disappear "eventually" as was asked. But for all practical purposes, a sample might be said to disappear over geologic time. Radon-222, an isotope of the radioactive inert gas, has a half-life of 3.8235 days. That means that in 3.8235 days, half of the 222Rn sample will be gone. In another 3.8235 days, half of that remaining 222Rn will be gone. And so on. Note that the radon-222 is undergoing radioactive decay to "disappear" as was asked. Additionally, each radon-222 atom that decays will have to undergo another 7 decay events to become a stable isotope of lead. And all of this is radioactive decay.
Does fermium-257 undergo nuclear decay?
Alpha decay to californium 253. The half life of fermium 257 is 100.5 days.
