The answer will depend on the power. The work can be done in one second or a billion years!
F = ma where m is mass and a acceleration. Distance is average velocity x time = 0.5 x time = 2 meters so time is 4 seconds. Acceleration is final velocity/time = 1/4 = 0.25 m/s/s.m = F/a = 5/.25 = 20 kilograms
Giving the cart an initial push will increase its velocity, leading to a higher acceleration due to the change in velocity over time. The acceleration will be influenced by both the initial push and any additional external forces acting on the cart.
The answer will depend on the power. The work can be done in one second or a billion years!
First, calculate the acceleration using the formula acceleration = net force / mass. Plug in the values to get acceleration. Next, use the kinematic equation, displacement = (initial velocity * time) + (0.5 * acceleration * time^2), where initial velocity is 0 since the cart starts at rest. Plug in the calculated acceleration and time to find the displacement of the shopping cart.
6-36 months
Distance = Rate X Time so, rearrange algebraically; Time = Distance/Rate = 583 meters/53 meters/s ( meters cancel ) = 11 seconds
Power = (energy) / (time) = (35 x 5) / 19 = 175 newton-meters / 19 seconds = 9.2105 watts (rounded)
To calculate the time it takes to travel 300 meters at a speed of 10 meters per second, you can use the formula: time = distance/speed. Plugging in the values, time = 300 meters / 10 meters per second, which equals 30 seconds. Therefore, it would take 30 seconds to travel 300 meters at that speed.
depends how fast you can run
7.14 seconds.
You have to unlock one expert staff ghost in time trials
Because the sound a cart makes is never a criteria for anyone buying a cart, and it sure should be. The noise can be deafening. If there was a place with QUIET carts, I would shop there if only to have a quiet cart. I have thought about solving this problem for a long time. I think for only $10 per cart, I could fix this problem and save the ears from that deafening noise permanently.