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Presumably the "stick" is a square piece of wood that's 5 ft in length?

Wastage = Volume of wood - Volume of cylinder

First we have to find the radius of the cylinder and this is done by square rooting 10 and dividing the answer by 2 which comes to about 1.58113883 ins.

Wastage = 10*60 - pi*1.581138832*60 (5 ft = 60 inches)

Wastage = 128.761102 cubic inches.

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Q: How much wood is to be wasted in turning out the largest possible cylindrical rod from a stick whose uniform square cross-section area is 10 sq in and whose length is 5 ft?
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