Weight of a mass of 50 kg = [ m g ] = (50 x 9.8) = 490 newtons.
Work = force x distance = 490 x 4 = 1,960 newton meters = 1,960 joules
It depends on the weight. The work required in joules (kg*m2/s2) is equal to the force applied in newtons and the displacement, or distance, in meters. Thus, for an object that weights 1 N (multiply the weight of the object by the gravitational acceleration, 9.81 m/s2 to transfer to newtons) will require 1 N * 3 m = 3 J. Thus, the formula for work is: W = Fd "W" is the work done on the system. "F" is the force in newtons "d" is the displacement (or distance) of the object in meters.
700 x 4 = 2,800 newton-meters = 2,800 joules
78*6*9.8 N = 4586.4 N
Two meter sticks taped together LOL.
Well a bookcase or chair would be a perfect answer
The amount of work done is determined by an object's force times the displacement. In this case it is 28 Newton meters, or 28 Joules.
24000 joules
minimum 150 joules
84
25 joule
98 j
12250
360 joules
12250
C.50 j
25 N.m
It depends on the weight. The work required in joules (kg*m2/s2) is equal to the force applied in newtons and the displacement, or distance, in meters. Thus, for an object that weights 1 N (multiply the weight of the object by the gravitational acceleration, 9.81 m/s2 to transfer to newtons) will require 1 N * 3 m = 3 J. Thus, the formula for work is: W = Fd "W" is the work done on the system. "F" is the force in newtons "d" is the displacement (or distance) of the object in meters.