It could be: (5*5)+(5*5)+5 = 55
55/5 = 11 - (5+5) = 1
55+5/5+5/5
The only solution that I know of is a bit of a cheat:5*(5 + 5) - 5/(.5 recurring).
55 plus 5/5
5 - 5 + 5 - 5 + 5 = 5
(55-5)/(5+5)
55 + 5*5 + 5 = 85.
55/5 = 11 - (5+5) = 1
55 + 5/5 = 56
Examples of sums using four fives to get 80:55+5×55!!×5+√(5×5)(55-5!!)/.5(5×5-5!!)/.55!-5×5-5!!((5!!/5)!)!/5×.(5)
55+5/5+5/5
55/5 - 5 = 6
Two solutions are :- 55/5 - 5 = 11 - 5 = 6 and √(5 x 5) + 5/5 = 5 + 1 = 6
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(.5+.5)/.5+(.5+.5)/.5
55 plus 5/5
5 - 5 + 5 - 5 + 5 = 5