(5 - 5/5)/.5
Two fives and four ones
6 fives
One possible solution: (3 + 3)*(1*3/3 + 3) = 6 * 4 = 24
4 fives of 25 = (4*5)*25 = 20*25 = 500
4 fives, which would leave you with 0.4 fives, which would leave you with 0.4 fives, which would leave you with 0.4 fives, which would leave you with 0.4 fives, which would leave you with 0.4 fives, which would leave you with 0.
The square root of (4 times 4) plus (4 divided by 4)
5-1/5= 4 4/5 *5 = 24
The probability of getting three fives in the first three rolls and non-fives in the next three rolls is; P(5,5,5,N5,N5,N5) = 1/6 x 1/6 x 1/6 x 5/6 x 5/6 x 5/6 = 0.002679... The number of different order in which the fives can come out is given by; 6C3 = 6!/[3!∙(6-3)!] = 20 So the probability that in 6 rolls of a fair die exactly three fives (in any order) will come out is; P(three fives any order) = (20)∙(1/6)3∙(5/6)3 = 0.05358... ~ 5.4%
Times. Four of fives is four lots of fives of 4 times five which is 20.
12.
5 x 5 = 25... 25 + 5 = 30.... 30 / 5 = 6.