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He is 4/3 of David's age.

The original version of this question has a sum of their ages, which would allow you to get a numerical answer. (e.g. sum of 56, ages are 32 and 24).

If James is 8, David is 6 - when James was 6, David was 4

If James is 12, David is 9 - when James was 9, David was 6

J = 2 [ D - (J-D)]

J = 2 (2D-J)

J = 4D - 2J

3J = 4D

J = 4/3 D

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10y ago
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Q: How old is James if he is twice as old as David was when James was as old as David is now?
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