explain the procedure for sign modulus method and 2's complement method for storing positive and negative numbers?
if the modulus (just the value ignoring the signs) of the negative number is larger than the positive number, adding the two will get you a negative number, if the positive number is larger, than modulus of a negative number you will have a positive. Can be easily demonstrated on a number line. yes
At the basic level, the modulus of a number or expression is simply the value of the number or of the expression. For a positive number the modulus is the number, for 0 it is 0, and for a negative number, x, it is -x (which is positive).
The positive number is always greater. However, the modulus of a negative number may be greater. Here is the number line. -infinity,.... -5,-4,-3,-2,-1, 0,+1,+2,+3,+4,+5 .... + infinity. So reading the number line, +2 > -4 . However, the modulus of '-4' is greater than the modulus of +2. . It is written as |-4| > |+2|, that is the number four is greater than the number two. Note the pair of vertical lines. NB I have put in the positive (+) sign to compare against the negative (-), however, a number that does not show a sign is read as positive(+).
The modulus would be described as the distance between, it is without direction and would therefore always be positive.
they do if you want them to.
psi is a complex numbers so its square will be negative(i^2=-i).. we take modulus of psi^2..as probability cannot be negative..
In mathematics, the modulus of a real number is its numerical value without regard to its sign. So, for example, 3 is the absolute value of both 3 and −3. When graphing a modulus function, f(|x|), graph the function f(x) ignoring the modulus and simply reflect any values below the x-axis (negative values) so they become positive.
(+)13 does NOT equal (-13). However, their modulii (plural of modulus) are equal at '13' . It is written as as a value -13 < +13 However the modulii is written as |-13| = |+13| note the use of vertical lines, because the numerical value is the same.
never heard of a negative modulus. Some special class polymers have negative Poisson ratio so when you pull on it gets wider inserted of narrower, but I know of none that get shorter when you pull on it
There are several ways to determine if an integer is even or odd. The most efficient method is to simply check if the low-order bit is set or not. If it is, the number is odd, otherwise it is even. bool is_odd (int num) { return (num & 1); } However, if the system uses ones-complement notation to represent negative values this won't work because ones-complement has two representations of the value zero (one positive and one negative), even though zero is neither positive nor negative but is an even number. Most systems these days use twos-complement notation so this is rarely an issue but it's worth keeping in mind. The most generic solution is to divide the value by 2 and check the remainder using the modulus operator (%). If there is a remainder, the value is odd, otherwise it is even.
Yes, although it is not commonly possible. A textbook source is available under "Related Link".
there are different types of modulus it depends on what types of stress is acting on the material if its direct stress then then there is modulus of elasticity,if tis shear stress then its modulus of rigidity and when its volumetric stress it is bulk modulus and so on