-8
9x2 - 28x + 20 = 9x2 - 18x - 10x + 20 = 9x(x - 2) - 10(x - 2) = (9x - 10)*(x - 2)
The decibel (dB) scale is logarithmic. An increase of power by a factor of 10 is an increase of +10 dB. If power increases by a factor of 100, that is equivalent to +20 dB.The decibel (dB) scale is logarithmic. An increase of power by a factor of 10 is an increase of +10 dB. If power increases by a factor of 100, that is equivalent to +20 dB.The decibel (dB) scale is logarithmic. An increase of power by a factor of 10 is an increase of +10 dB. If power increases by a factor of 100, that is equivalent to +20 dB.The decibel (dB) scale is logarithmic. An increase of power by a factor of 10 is an increase of +10 dB. If power increases by a factor of 100, that is equivalent to +20 dB.
20
4x2-20+25 = (2x-5)(2x-5) when factored with the help of the quadratic equation formula.
The load (in this case, your led lighting) determines its own power factor. While you can improve the power factor (move it towards unity) at the terminals, you are not actually changing the power factor of the load.
380
Your question cannot be answered, unless the power factor of the load is specified. Since true power(measured in watts) is the product of apparent power(measured in volt amperes) and the power factor of the load.So, given your figure of an apparent power of 20 kV.A(not 'kva'*), the corresponding value of true power could (theoretically!) range from20 kW at a power factor of 1.0, to0 kW at a power factor of 0.(*The correct symbol for kilovolt ampere is 'kV.A', not 'kva', and the correct symbol for kilowatt is 'kW', not 'kw'.)
20 to the second power is more commonly known as 202 or 20 squared. Squaring is calculated by taking two of the number and multiplying them together. In this case, 20x20=400 and so 20 to the 2nd power is 400.
It equals 200 because 20x20 equals 200
(20-1-6-2)2 = 112 = 121
20 is not a factor of 30
No, 20 has 5 as a factor.