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How to find the equation of the line tangent to the graph of y is equal to 21 times e with an exponent of 4x divided by x at the point x is equal to 1 and you need the slope and what y is equal to?
Wiki User
∙ 12y ago
My interpretation of the wording is:
. . . .21e4x
y = ---------
. . . . . .x
From here, just take the derivative, using the quotient rule:
y' = 21* [4e3x * ex * x - 1 * e4x] / x2
= 21 * [e4x](4x - 1) / x2
When x=1
y = 21e4
At x=1, gradient = 63e4
Point gradient formula gives:
y - 21e4 = 63e4 * (x - 1)
y = 63e4x - 42e4
That should be the answer.
Wiki User
∙ 12y ago
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