As the other contributor mentioned, the standard formula for the period (T) of a simple pendulum is
T = 2*pi*sqrt(L/g)
so the period is inversely proportional to the square root of acceleration 'g'. But for practical purposes (as implied by the question) we can replace 'g' with another value, the apparent acceleration due to gravity, 'ga'. This value also takes into account the rotational speed and the distance from the center of the gravitational mass
ga = GM/r**2 - (w**2)*cos(LAT)
where:
w = angular velocity of the earth's rotation
= 2*pi/(24*3600) [rad/s]
LAT = observer's latitude (0=equator, 90deg=pole)
G = universal gravitation constant
M, r = mass, radius of planet/satellite/star we are on
Thus, the period of a simple pendulum is inversely proportional to to the sqare root of 'ga'. And this value varies with latitude, mass and distance.
So then let's answer the questions!
a) as we increase the height from sea level, the radius increases, reducing the 'ga' and this increases the period, T
b) as we go to the pole, LAT = 90deg, and cos(LAT) goes to zero. We thus INCREASE 'ga' and decrease the period
c) at the equator, LAT = 0 and cos(LAT) = 1, so we have a minimum value for 'ga', this increases the period
d) on the moon, our rotational velocity is much less (1 rev per 27.3 days) and the M is much smaller, and the r is much smaller! We are told that the 'ga' will be about 1/6 of the Earth's value, so the period will increase.
e) Here the M is colossal, so if we could withstand the heat and gravitational forces, 'ga' is much larger, so period will decrease.
It's faster at sea level and slower at the top of a mountain.
As the force of gravity increases the period would decrease. So shortest period on the sun (if you can keep it intact), then sea level, then mountain top and then moon.
The period is not likely to be charged. However, it would change due to the weaker gravitational force on the moon. Since the surface gravity of the moon is 0.165 that of the earth, the period would increase by a multiple of 1/sqrt(0.165) = 2.462 approx.
A 2-meter pendulum at sea level has a period of 2.84 seconds.
The time period of oscillation of the pendulum is inversely proportional to the square root of the value of acceleration due to gravity (g) at that place. g is low at heights above the sea level. So T increases. Period increases. So frequency decreases. Hence the slow movenment.
Denser, heavier air.
..weigh less and the pendulum will swing at a slower rate. It might become more valuable (high mountain areas have less access to fine clocks than many sea level communities).
it will lose time. it slows as you change level....change of gravity
In order to find out blood level following a period of exercise one would need to purchase a blood glucose meter. This is a simple tool used by many diabetics to determine their blood glucose levels.
The number of each period correspond to the outermost energy level that contain electrons for elements in that period. Those in period 1 contain electron only in energy level 1 while those in period 2 contain electron in level 1 & 2. In period 3, electrons are found in level 1, 2, and 3 AN SO ON.....
Remember the formula used to calculate the gravitational potential energy of a mass given its mass and height above an arbitrary zero level isPEgravity = mghWhen a pendulum is pulled back from equilibrium through an angle θ, its height is calculated with the formulah = L - L cos θwhere θ is the angular displacementThe formula used to calculate the kinetic energy of a massive particle isKE = ½ mv2In the absence of non-conservative forces, such as friction or applied, external forces, the mechanical energy in a system is conserved. That isDuring the swing of a simple pendulum, when does the bob possess maximum PE?PE is maximum at the endpoints (maximum amplitude)During the swing of a simple pendulum, when does the bob possess maximum KE?KE is maximum at equilibrium (bottom position)During the swing of a simple pendulum, what is the magnitude of the bob's maximum velocity?Another way of looking at conservation of energy is with the following energy diagram. As you can see,the "purple" curve represents the pendulum bob's KE which during each cycle begins with an initial value of zero, increases to a maximum value, and then returns to zerothe "green" curve represents the PE of the bob which begins each cycle at a maximum value, then becomes zero as the bob passes through its equilibrium position, and returns to its maximum valuethe "brown" line represents the total energy of the pendulum bob that always remains constantIf a pendulum is initially released at an angle of 37º, at what angle will its PE and the KE be equal?25.9ºRefer to the following information for the next question.At any intermediate position during the oscillation, the pendulum bob would have both PE and KE.PEmax = PEintermediate + KEintermediate = KEmaxIf the pendulum was released at point A, derive an expression for the pendulum's instantaneous velocity at point B, an intermediate position in its swing.See the related lesson on vertical circles if you are asked to calculate the tension of the string during the pendulum's oscillation. Remember that a pendulum is merely the bottom half of a vertical circle! These conservation of energy methods are the easiest way to determine an object's speed so that tensions can be calculated.
level it up simple