0
How would you add together 1776 and 49 in two different ways but showing both calculations entirely in Roman numerals from start to finish?
Wiki User
∙ 9y ago
In todays modern configuration of Roman numerals 49 is now considered to be XLIX but the ancient Romans would have probably added the given numbers in either of the following formats:-
A: MDCCLXXVI+IL = MDCCCXXV => 1776+(50-1) = 1825.
B: MDCCLXXVI+XXXXVIIII = MDCCCXXV => 1776+49 = 1825.
For more complicated calculations the Romans would have used an abacus calculating device.
QED
Wiki User
∙ 9y ago
Add your answer:
Earn +20 pts
How would you actually add together 1666 and 1999 in two different ways entirely in Roman numerals throughout both calculations with explanations?
See answer to question: ' How do you add together 1666 and 1999 in two different ways using Roman numerals'
How would to add together 1999 and 3001 in two different ways showing both calculations entirely in Roman numerals?
When in Rome do as the Roman do and the ancient Romans would have probably added together 1999 and 3001 in either of the following ways:- IMM+MMMI = (V) => (2000-1)+3001 = 1000*5 = 5000 MDCCCCLXXXXVIIII+MMMI = (V) => 1999+30001 = 5000 Note that in todays modern configuration of Roman numerals 1999 is now considered to be MCMXCIX
How would you add together 51 plus 49 in two different ways and 51 minus 49 in two different ways but showing all calculations entirely in Roman numerals with explanations?
Doing arithmetic with Roman numerals is exasperating, and imho a pointless waste of time, except to demonstrate the obvious superiority of our "normal numbers," which use base-10 radix / positional notation that includes a zero digit as a placeholder. I'd venture to say science & technology -- commerce, too -- could never have developed in recent centuries if we still used Roman numerals for calculations. However, this web site explains some methods: http://turner.faculty.swau.edu/mathematics/materialslibrary/roman/
How would you add together 31 plus 19 in two different ways and 31 minus 19 in two different ways showing all four calculations entirely in Roman numerals?
The modern way of expressing 19 into Roman numerals is now XIX but the ancient Romans would have probably worked out the above calculations as follows: A: XXXI+IXX = L => 31+(20-1) = 50. B: XXXI+XVIIII = L => 31+19 = 50. C: XXXI-IXX = XII => 31-(20-1) = 12. D: XXXI-XVIIII = XII => 31-19 = 12.
How would you add together 1776 plus 1999 in two different ways and subtract 1776 from 1999 working out all three calculations entirely in Roman numerals?
It is now generally accepted that the modern way of expressing 1999 into Roman numerals is now MCMXCIX but the ancient Romans would have probably worked out the above as follows:- A: MDCCLXXVI+IMM = MMMDCCLXXV => 1776+(2000-1) = 3775 B: MDCCLXXVI+MDCCCCLXXXXVIIII = MMMDCCLXXV => 1776+1999 = 3775 C: MDCCCCLXXXXVIIII-MDCCLXXVI = CCXXIII => 1999-1776 = 223 The above calculations are fairly easy and straightforward but for more complicated calculations the Romans would have used an abacus counting device.
What is the sum of 1999 and 2014 added together in two different ways entirely in Roman numerals with explanations?
MIM + MMXIV = MMMXIII or MMCXCIX + MMXIII = MMMXIII There is only one way to write the solution (3013)
What are two different ways of adding together 1776 plus 199 plus 145 but working out both calculations entirely in Roman numerals?
Notwithstanding today's rules now governing the Roman numeral system that were introduced during the Middle Ages inasmuch that there exist credible evidence to suggest that the ancient Romans would have worked out the required calculations as follows:-MDCCLXXVI+CLXXXXVIIII+CXXXXV = MMCXX => 1776+199+145 = 2120VXXCCMMI+ICC+VCL = MMCXX => (2001-225)+(200-1)+(150-5) = 2120Note that the above calculations are fairly simple and straightforward but for more complicated calculations the Romans would have made use of an abacus calculating device.QED
How would you actually add together 1999 and 14 in two different ways entirely in Roman numerals with explanations?
Notwithstanding todays modern conversion of 1999 and 14 into Roman numerals which are MCMXCIX and XIV respectively inasmuch that there exist credible evidence to suggest that the ancient Romans would have added together the equivalent of 1999 and 14 in either of the following formats:- A: IMM+IXV = MMXIII => (2000-1)+(15-1) = 2013 B: MDCCCCLXXXXVIIII+XIIII = MMXIII => 1999+14 = 2013 Not that for more complicated calculations the ancient Romans would have used an abacus calculating device.
What is the sum of 999 plus 14 plus 1987 added together in two different ways but showing all work and answers entirely in Roman numerals?
Cmxcix + xiv + mcmlxxxvii = mmm. It should be all in capital letters, but the system changed them.
How would you add together 1776 plus 99 plus 1907 in two different ways showing both completed calculations entirely in Roman numerals with reasons why?
When in Rome do as the Romans do because the ancient Romans would have probably added together the given numbers in either of the following configurations:- As: MDCCLXXVI+IC = MDCCCLXXV => 1776+(100-1) = 1875. MDCCCLXXV+CMMVII = MMMDCCLXXXII => 1875+(2007-100) = 3782. Or as: MDCCLXXVI+LXXXXVIIII = MDCCCLXXV => 1776+99 = 1875. MDCCCLXXV+MDCCCCVII = MMMDCCLXXXII => 1875+1907 = 3782. Note that in todays modern configuration of Roman numerals 99 and 1907 are now considered to be XCIX and MCMVII respectively. The above calculations are fairly simple and straightforward but for more complicated calulations the Romans would have used an abacus counting device.
What is the sum of 1999 plus 19 added together in four different ways entirely in Roman numerals giving explanations?
Under today's modern rules now governing the Roman numeral system we would convert the equivalent of 1999 and 19 into Roman numerals as MCMXCIX and XIX respectively which makes them almost impracticable for arithmetical operations but there is historical evidence to suggest that the ancient Romans would have probably worked out the required calculations in any of the following formats:-IMM+IXX = MMXVIII => (2000-1)+(20-1) = 2018MDCCCCLXXXXVIIII+IXX = MMXVIII => 1999+(20-1) = 2018IMM+XVIIII = MMXVIII => (2000-1)+19 => (2000-1)+19 = 2018MDCCCCLXXXXVIIII+XVIIII = MMXVIII => 1999+19 = 2018Note that the above calculations are fairly simple and straight forward but for more advanced calculations the Romans would have used an abacus calculating device.QED
How would you add together 3001 plus 1999 in two different ways and 3001 minus 1999 in two different ways but showing all four calculations entirely in Roman numerals?
In today's modern configuration of Roman numerals 1999 is now considered to be MCMXCIX but the ancient Romans would have probably worked out the above as in the following formats:- A: MMMI+IMM = (V) => 3001+[2000-1] = 5000. B: MMMI+MDCCCCLXXXXVIIII = (V) => 3001+1999 = 5000. C: MMMI-IMM = MII => 3001-[2000-1] = 1002. D: MMMI-MDCCCCLXXXXVIIII = MII => 3001-1999 = 1002.
