7 divides evenly into 140 with no remainder.
22 x 5 x 7
You know that 7 isn't a factor of 291 because the quotient of 291 and 7 isn't a whole number.
No. Only 14 and multiples of 14 have both 7 and 2 as factors.
Divide 7 into 291. If it comes out evenly, it's a factor. It doesn't, so it's not.
There isn't an easy test for 7. You have to divide it. 7 is not a factor of 291.
it would be 7
If that was - 10x + 21, it would factor to (x - 3)(x - 7) If that was + 10x + 21, it would factor to (x + 3)(x + 7) As it is, the solutions are irrational.
Divide 7 into 29. If the answer is an integer with no remainder, it's a factor.
No.
(q - 7)(4q + 1)
Since 4 x 7 is 28, you know that 7 isn't a factor of 29. Since 29 is a prime number, you know that 7 isn't a factor of it. To be perfectly sure, divide 7 into 29. If the answer is an integer, it's a factor.
7 doesn't have an easy test. But when I see that 291 is made up of 280 + 11, I know that 7 is not a factor.