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The hexagon will consist of 6 equilateral triangles with 3 equal sides of 20 cm and 3 interior angles of 60 degrees.

Using the area formula: 0.5*20^2 *sin(60)*6 = 1039.230485 square cm.

The hexagon will also have 12 right angle triangles with a base of 10 cm and an hypotenuse of 20 cm.

Using Pythagoras' theorem the height of each triangle is the square root of 300.

Using another area formula: 0.5*10*square root of 300*12 = 1039.230485 square cm.


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Q: How would you find the surface area of a regular hexagon with a perimeter of 120 cm in two different ways?
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