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How would you get 206square feet if you have a perimeter of 72 yards but using a dimensions?
72 yards = 72*3 = 216 feet.
So you require a rectangle whose area is 206 sq feet and whose perimeter is 216 feet.
Thus, if the sides are x and y, then xy = 206 and 2(x+y) = 216 ie x+y = 108
This gives rise to the quadratic: x2 - 108x + 206 = 0 and the solution gives the dimensions of the required rectangle as 1.94234 ft x 106.0577 ft.
All this assumes, with no justification, that the required shape is a rectangle and not a circle or an irregular shape.
What else can I help you with?
How would doubling the dimensions effect a parallelogram in perimeter and area?
When all of the linear dimensions are doubled . . .-- the perimeter is also doubled-- the area is multiplied by 22 = 4.
What is the perimeter of 1437 square meters?
The area doesn't tell you the dimensions or the perimeter. It doesn't even tell you the shape. The shortest perimeter that could enclose that area would be a circle. The shortest perimeter with straight sides would be a square. If it's a rectangle, then there are an infinite number of them, all with different dimensions and different perimeters, that all have the same area.
What are the dimensions of a garden that has a 36ft perimeter and an area of 81sq ft?
9 feet by 9 feet would hold true for its perimeter and area.
What is the perimeter of a normal house?
The perimeter of a normal house depends on its specific dimensions and shape. For a rectangular house, the perimeter can be calculated by adding the lengths of all sides, using the formula P = 2(length + width). For example, if a house measures 30 feet in length and 20 feet in width, the perimeter would be 100 feet. However, for irregularly shaped houses, the perimeter would require measuring each side individually.
How do you maximize the area given the perimeter?
In the case of a rectangle, you would maximize the area given the perimeter by making the dimensions equal. In other words, you would make the rectangle into a square. However, to truly maximize the area, you would make the perimeter a perfect circle.
What shape has an area of 12 and a perimeter of 16?
The shape that has an area of 12 and a perimeter of 16 is a rectangle. To find the dimensions of the rectangle, you can set up equations using the formulas for area and perimeter. Let the length of the rectangle be L and the width be W. The equations would be: 2L + 2W = 16 (perimeter) and LW = 12 (area). Solving these equations simultaneously will give you the dimensions of the rectangle.
How do you solve the problem Nu is disigning a rectangular sandbox The bottom is 16 square feet which dimensions requie the least amount of material for the sides of the sandbox?
Ok, an important part of this is that shapes can be categorized into multiple groups. It goes something like this in this case: Quadrilateral V Rectangle V Square When dealing with shapes, regular polygons always have less perimeter than irregular for the same area. Here, a square would have a perimeter of 16, with 4x4 dimensions; the next closest rectangle would have a perimeter of 20, with dimensions of 8x2; the last rectangle you could make would have a perimeter of 34, with dimensions of 16x1.
What is the perimeter of 5000 square meters?
The area doesn't tell you the dimensions or the perimeter. It doesn't even tell you the shape. The shortest perimeter that could enclose that area would be a circle. The shortest perimeter with straight sides would be a square. If it's a rectangle, then there are an infinite number of them, all with different dimensions and different perimeters, that all have the same area.
What are the perimeter dimensions on 4000 square feet?
They could be almost anything. A strip of land 1 foot by 4000 feet would have a perimeter of 8002 feet. A plot 50 x 80, still 4000 square feet, would have a perimeter of 260 feet.
A triangle-shaped machine part has sides of 212 inches 314 inches and 5 inches. The triangle's perimeter is?
The dimensions given would not form a triangle and so no perimeter is possible
What would be one set of possible dimensions for an isosceles triangle with a perimeter of 12 units?
5, 5 and 2 units
If farmer Dan has 100 feet of fencing write an inequality to find the dimensions of the rectangle with the largest perimeter that can be created using 100 feet of fencing?
To find the dimensions of a rectangle with the largest perimeter using 100 feet of fencing, we can express the perimeter ( P ) of a rectangle in terms of its length ( l ) and width ( w ) as ( P = 2l + 2w ). Since the total amount of fencing is 100 feet, we set up the inequality ( 2l + 2w \leq 100 ). Simplifying this gives ( l + w \leq 50 ). The dimensions that maximize the area (which is a related concept) would be when ( l = w = 25 ) feet, creating a square shape.
