35x*2=5x
Well, I can only think of one way to solve this. Forgive if I'm wrong 'cause I'm only in 9th grade. I've tried it the other way where you solve the equation for zero, but it didn't work. So here's the only way I saw, I apologise if it is wrong.
35x*2=5x
-5x......-5x
30x*2=0
.......-2-2
..30x=-2
...30x/30-2/30
x=-1/15
21x3-35x2+14x = 7x(3x2-5x+2)
5x^2
35x2-36x-32 = (5x-8)(7x+4) when factored. 35*-32 = -1120 = -56*20 since -56+20 = -36 (35x - 56)(35x + 20) divide by 7 and 5 the coefficients of the two binomials (5x - 8)(7x + 4) or 35x2 - 56x + 20x - 32 = 7x(5x - 8) + 4(5x - 8) = (5x - 8)(7x + 4)
128
(7x - 5)(5x - 2)
-(5x + 3)(7x - 2)
5x-19 = 16 5x = 16+19 5x = 35 x = 7
5x = 25Divide both sides by 5:x = 5
30
x=7
-5x+50 = 25 -5x = 25-50 -5x = -25 x = 5
5x(x^4+7x+4)