Time is distance/speed. Call the distance "d". So d/200=d/250 + 1.
Collect the terms in d together: d(1/200-1/250)=1
Multiply both sides by 200 x 250 (ie the common denominator on the left)
That's d(250-200) = 200 x 250 which is 50d =200x250 or d =4x250 =1000 miles
Check: 1000m at 200mph=5h, 1000m at 250mph =4h : difference 1h. OK,
You don't use unknown variables to solve an equation. The purpose of solving an equation is to find the value of the variable so that it's no longer unknown.
The population of Saint-Solve is 395.
a is the coefficient of the x2 term. If is a = 0, then it is no longer a quadratic - it is just a linear equation, and the quadratic formula will not work to solve it.
Sure. You can always 'solve for' a variable, and if it happens to be the only variable in the equation, than that's how you solve the equation.
you don't answer an equation, you solve an equation
The area of Saint-Solve is 5,840,000.0 square meters.
solve it
If you solve such an equation for "y", you get an equation in the slope-intercept form.
It is not an equation if it does not have an equals sign. You could simplify it but not solve it.
How do you use division to solve a multiplication equation?Answer this question…
you can only solve for one in an equation so it can equal something
There is no such thing as "solving integers". You can solve an equation, which means finding all the unknowns in that equation, but you can't solve an integer.