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Q: How would you write 116 as a product of prime numbers?

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Related questions

13*3

Prime factorization

98 = 2*7^2.

2x2x2x3

2x2x3x5

2x2x3x3x3

That's called the prime factorization.

Prime factorization of 27 = 3x3x3

As a product of its prime factors: 2*2*19 = 76

2x2x2x2x3x3=144

2 x 2 x 3 = 12

As a product of its prime factors: 2*3*5*7 = 210

The product of prime numbers for 336 is:2x2x2x2x3x7This is because all of that sum equals the total of 3362x2x2x3x7=336

7*3*3

38 = 2 * 19

2 x 29

As a product of its prime factors in exponents: 22*3*52 = 300

1386 is the product of 2 x 3 x 3 x 7 x 11, all of which are prime numbers.

It is: 2*2*11 = 44

ANSWER: 3 * 5 * 5 = 75

9 = 3 x 3

It is: 2*5*7 = 70

It is: 2*3*7 = 42

7*13*2*2

33 = 3 x 11