(2p)2 = 4p2
10
Nitrogen has 2s^3 2p^3 valence electrons so the answer would be 3
2p+10 = 8p-14 2p-8p = -14-10 -6p = -24 p = 4
The GCF is 2p.
2p
no. you would solve and get -80=-2p or 80=2p. thus resulting in p=40
3p = 2p + 12 subtract 2p from both sides 3p - 2p = 2p - 2p + 12 1p = 12 p = 12 this is how you solve this problem.
You would have 7p
20p, 2p, 2p, 2p, 1p.
There are 31 ways:1p × 211p × 19 + 2p × 11p × 17 + 2p × 21p × 16 + 5p × 11p × 15 + 2p × 31p × 14 + 2p × 1 + 5p × 11p × 13 + 2p × 41p × 12 + 2p × 2 + 5p × 11p × 11 + 2p × 51p × 11 + 5p × 21p × 10 + 2p × 3 + 5p × 11p × 9 + 2p × 61p × 9 + 2p × 1 + 5p × 21p × 8 + 2p × 4 + 5p1p × 7 + 2p × 71p × 7 + 2p × 2 + 5p × 21p × 6 + 2p × 5 + 5p1p × 6 + 5p × 31p × 5 + 2p × 81p × 5 + 2p × 3 + 5p × 21p × 4 + 2p × 6 + 5p × 11p × 4 + 2p × 1 + 5p × 31p × 3 + 2p × 91p × 3 + 2p × 4 + 5p × 21p × 2 + 2p × 7 + 5p × 11p × 2 + 2p × 2 + 5p × 31p × 1 + 2p × 101p × 1 + 2p × 5 + 5p × 21p × 1 + 5p × 42p × 8 + 5p × 12p × 3 + 5p × 3
2s and 2p 2p can be further divided into 2p(x), 2p(y), and 2p(z), depending on which axis you look at.
To calculate -2p(-38), you first need to know the value of the variable ( p ). If ( p ) is a constant, simply multiply -2 by ( p ) and then by -38. For example, if ( p = 1 ), then -2p(-38) would equal 76. Without a specific value for ( p ), the expression remains as is: -2p(-38).