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6c + 7h = 2500 . . . . . (A)

13c + h = 2310 . . . . . (B)

By (B), h = 2310 - 13c

Substituting this value in (A) gives

6c + 7*(2310 - 13c) = 2500

or 6c + 16170 - 91c = 2500

that is, 85c = 13670

so that c = 16014/17

Then h = 2310 - 13c gives

h = 2310 - 2090156/221 = 21965/221.

The answers suggest that there is an error in the number of animals bought.

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Q: How would you write the equation for one cow and one horse when one farmer buy 6 cows and 7 horses for 2500 and the other 13 cows and 1 horse for 2310?
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