The answer depends on what form you wish to convert binary and hex 2011 to.
1. represent every individual digit of given hexadecimal in binary form like this 4---------> 0100 8---------> 1000 7---------> 0111 2. combine the individual binary digits in order to get the binary of given hexadecimal number 487 ------------> 0100 1000 0111 ( required binary number )
117
hexadecimal can express 16 bit binary in 4 place form, not 16.
(01110111)2 = hexadecimal byte 77 = (119)10
Certainly! To convert a hexadecimal number to a binary number using an 8085 microprocessor, you would typically use a series of instructions involving logical operations such as AND, OR, and shifts. One common approach is to isolate each hexadecimal digit, convert it to its binary equivalent, and then combine the binary values to form the final binary number. The specific program code would depend on factors such as the starting memory address, the input method, and the desired output format.
Each hexadecimal digit (or nybble) is the equivalent of 4 binary digits (or bits) with a decimal value of 0-15. Convert each nybble into (4) binary (digits) and string them together, remembering the conversion of decimal 0-15 to binary: Hex -> Dec -> Binary 0 -> 00 -> 0000 1 -> 01 -> 0001 2 -> 02 -> 0010 3 -> 03 -> 0011 4 -> 04 -> 0100 5 -> 05 -> 0101 6 -> 06 -> 0110 7 -> 07 -> 0111 8 -> 08 -> 1000 9 -> 09 -> 1001 A -> 10 -> 1010 B -> 11 -> 1011 C -> 12 -> 1100 D -> 13 -> 1101 E -> 14 -> 1110 F -> 15 -> 1111 So to convert 0x6AF to binary: 6 -> 0110 A -> 1010 F -> 1111 => 0x6AF = 0110 1010 1111 = 011010101111 (without the spaces showing the hex nybbles)
111 = 1101111
Transmission Media
its easy to convert a given binary number into haxadecimal form.
Binary coded decimal (BCD) is easier to convert between displayed or printed form than is pure binary.
They convert the command given by us in the form of binary
Expressed as a sum in hexadecimal form, F + D = 1C.