Yes, every counting number is a multiple of itself.
Yes it is, because the number 1 is the multiplicative identity for the set comprising counting numbers.
That's the "square" of the number. With counting numbers, the square will always be another counting number.
Not counting 57 itself, 56 & 58.
No. 2 is a multiple of only two numbers, one and itself.
Since multiples are the numbers produced when that number is repeatedly added. if we add 1 repeatedly we can obtain any natural number. So the answer is YES
Two or more numbers are needed to find the LCM
That's the "square" of the number. With counting numbers, the square will always be another counting number.
A prime number can be multiplied by any other numbers because all whole numbers are the product of prime numbers.
The least common multiple is one of the numbers when one of the numbers is a multiple of the other.
1 is only a multiple of itself.
Not counting 57 itself, 56 & 58.
Yes, all number with have the factor 1 and itself.
Since 120 is a multiple of itself, all you need to do is pair it with any other factor of 120. 120 and 60 have an LCM of 120.
No. 2 is a multiple of only two numbers, one and itself.
Prime numbers are those numbers which are only divisible by one and itself. For eg 2,3,5,7 ....
No. 7, itself, is a multiple of 7 [7 * 1 = 7] and it is not a composite.
A prime number is only divisible by itself and 1... A squared number is a multiple of itself - and thus is not a prime number !
Either add it to itself over and over or multiply it by consecutive counting numbers.