Yes, every counting number is a multiple of itself.
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Yes it is, because the number 1 is the multiplicative identity for the set comprising counting numbers.
That's the "square" of the number. With counting numbers, the square will always be another counting number.
Not counting 57 itself, 56 & 58.
No. 2 is a multiple of only two numbers, one and itself.
Since multiples are the numbers produced when that number is repeatedly added. if we add 1 repeatedly we can obtain any natural number. So the answer is YES
Two or more numbers are needed to find the LCM