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Yes, every counting number is a multiple of itself.

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7y ago
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7y ago

Yes it is, because the number 1 is the multiplicative identity for the set comprising counting numbers.

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Q: IS EVERY COUNTING NUMBERS A MULTIPLE OF ITSELF explain?
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Related questions

What is the product of a counting number and itself?

That's the "square" of the number. With counting numbers, the square will always be another counting number.


Can a prime number be multiple of any other number except itself explain why or why not?

A prime number can be multiplied by any other numbers because all whole numbers are the product of prime numbers.


When is the least common multiple one of itself?

The least common multiple is one of the numbers when one of the numbers is a multiple of the other.


Is 1 a multiple of any numbers?

1 is only a multiple of itself.


What two whole numbers are closest to 57?

Not counting 57 itself, 56 & 58.


Do all counting numbers have one as a factor?

Yes, all number with have the factor 1 and itself.


Is two a multiple of every number?

No. 2 is a multiple of only two numbers, one and itself.


How can you explain prime numbers?

Prime numbers are those numbers which are only divisible by one and itself. For eg 2,3,5,7 ....


How can you find the second common multiples of two numbers from the first?

To find the second common multiple of two numbers, you first need to identify the least common multiple (LCM) of the two numbers. The LCM is the smallest number that is a multiple of both numbers. Once you have the LCM, you can then find the second common multiple by adding the LCM to the LCM itself. This will give you the second common multiple of the two numbers.


Is every multiple of 7 a composite numbers?

No. 7, itself, is a multiple of 7 [7 * 1 = 7] and it is not a composite.


Why can't prime numbers be squared numbers?

A prime number is only divisible by itself and 1... A squared number is a multiple of itself - and thus is not a prime number !


How do you obtain the set of multiples of a given number?

Either add it to itself over and over or multiply it by consecutive counting numbers.