By definition one calory is needed to heat up one gram of water exactly one degree celsius.
So 100 cal will heat 10 g. of water up for 10oC:
Temperature after heating will be 15 oC + 10oC = 25 oC
The temperature on Ceres varies from -38 Celsius (highest), -105 Celsius (average), -114 Celsius (lowest).
480 degrees Celsius
20 degrees Celsius is a measurement of temperature - air at 20 degrees Celsius is a comfortable temperature for people to live in. 20 degrees Celsius = 68 degrees Fahrenheit
The answer is 0
-5C
To transform 1 gram of ice at 0 degrees Celsius to 1 gram of water vapor at 100 degrees Celsius, 720 calories are added (absorbed). There are no calories released during the process.
Change in temp = 28° - 22° = 6°. Heat capacity of liquid water is 1 calorie per gram per degree(C).So the energy absorbed is (50) x (6) = 300 calories.
The number of calories required will depend on the mass of water which is to be heated.
Liquid water absorbs 1 calorie per (gram °C)Temperature difference = 100°C - 23°C = 77°C(50 g) * (77°C) * (1 cal/g/°C) = 3850 calories
115.2
A calorie is the amount of heat you need to raise the temperature of one gram of water by one degree Celsius. Assuming you are raising the temperature of the water from twenty degrees Celsius to ninety-nine degrees Celsius, it would take 20,000 calories. To calculate this, subtract 20 from 99. This is the amount of degrees you need to raise the temperature of the water by. Then multiply that number by 256, the amount of water in grams. You should get 20,244 calories. In significant digits, your answer should be 20,000 calories.
105C
Zero degrees Celsius.
25 degrees Celsius.
35 degrees Celsius.
The Celsius temperature of 32 degrees Fahrenheit would be 0 degrees.
32 degrees Fahrenheit = 0 degrees Celsius