answersLogoWhite

0


Best Answer

By definition one calory is needed to heat up one gram of water exactly one degree celsius.

So 100 cal will heat 10 g. of water up for 10oC:

Temperature after heating will be 15 oC + 10oC = 25 oC

User Avatar

Wiki User

13y ago
This answer is:
User Avatar
More answers
User Avatar

AnswerBot

2w ago

The temperature of the water would reach 25°C. The specific heat capacity of water is 4.18 J/g°C, so to calculate the temperature change, we can use the formula: Q = mcΔT, where Q is the heat absorbed, m is the mass of water, c is the specific heat capacity of water, and ΔT is the temperature change. By rearranging the formula to solve for ΔT, we find that the temperature change is 10°C. This means the final temperature would be 25°C (15°C + 10°C).

This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: If 100 calories of heat are absorbed by 10g of water at 15 degrees Celsius its temperature will be 21 or 23 C or 25 C or 27 C and explain the process?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

How many calories are released during the process of condensation?

To transform 1 gram of ice at 0 degrees Celsius to 1 gram of water vapor at 100 degrees Celsius, 720 calories are added (absorbed). There are no calories released during the process.


Heat is measured in Celsius degrees true or false?

False. Heat is measured in units of energy such as calories or joules, not in degrees Celsius. Temperature, on the other hand, is measured in degrees Celsius.


How much energy is absorbed by 50 grams of water if the temperature changes from 22 degrees celsius to 28 degrees celsius?

Change in temp = 28° - 22° = 6°. Heat capacity of liquid water is 1 calorie per gram per degree(C).So the energy absorbed is (50) x (6) = 300 calories.


If the temperature is currently 20 degrees Celsius and it decreases by 30 degrees what will the temperature be in Celsius?

If the temperature decreases by 30 degrees Celsius from 20 degrees Celsius, the new temperature will be -10 degrees Celsius.


How much heat is absorbed in calories in 50 grams of water with 23 degrees Celsius to 100 degrees Celsius?

Liquid water absorbs 1 calorie per (gram °C)Temperature difference = 100°C - 23°C = 77°C(50 g) * (77°C) * (1 cal/g/°C) = 3850 calories


How many calories of heat would it take to raise the temperature of 256 grams of water from 20 degrees to 99 degrees?

A calorie is the amount of heat you need to raise the temperature of one gram of water by one degree Celsius. Assuming you are raising the temperature of the water from twenty degrees Celsius to ninety-nine degrees Celsius, it would take 20,000 calories. To calculate this, subtract 20 from 99. This is the amount of degrees you need to raise the temperature of the water by. Then multiply that number by 256, the amount of water in grams. You should get 20,244 calories. In significant digits, your answer should be 20,000 calories.


If 75 grams of water at 30 degrees Celsius absorbs 900 calories what will be the new temperature?

105C


What is the temperature drop from 3 degrees Celsius to -7 degrees Celsius?

The temperature drop from 3 degrees Celsius to -7 degrees Celsius is 10 degrees.


If the temperature is 95 degrees Fahrenheit outside what is the temperature in degrees celsius?

35 degrees Celsius.


If a temperature is 32 degrees what is the celsius?

The temperature is 0 degrees Celsius.


If a temperature is 32 degrees Fahrenheit what is it in Celsius temperature?

Zero degrees Celsius.


What would be the temperature of ice in degrees Celsius?

The temperature of ice is 0 degrees Celsius. At this temperature, ice is in its solid form.