Molarity = moles of solute/Liters of solution
Find moles glucose, which is molecular formula------C6H12O6
154 grams C6H12O6 (1 mole C6H12O6/180.156 grams)
= 0.8548 moles C6H12O6
Molarity = 0.8548 moles C6H12O6/1 Liter
= 0.855 M glucose
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Molarity = moles of solute/liters of solution 2500 milliliters = 2.5 liters ------------------------------------ 12.2 grams SrCl2 (1 mole SrCl2/158.52 grams) = 0.07696 moles strontium chloride -------------------------------------------------------------------------------------------------------- so, Molarity = 0.07696 moles SrCl2/2.5 liters = 3.07 X 10 -2 M SrCl2 -------------------------------------
If 1,1 is grams the molarity is 0,317.
Increasing the amount of the solute in the solution the molarity and the density of this solution increases.
Find moles of glucose. 32.8 grams C6H12O6 (1 mole C6H12O6/180.156 grams) = 0.18206 moles C6H12O6 Molarity = moles of solute/Liters of solution M = 0.18206 moles C6H12O6/1.0 L = 0.18 M C6H12O6
Molarity= moles/Liters To change grams to moles you divide by the mole weight which is listed on the periodic table. Mol= grams/mol weight The Mole weight of Magnesium Chloride is 59.8 grams/mol Mol=128g/59.8 Mol=2.14 Now, you put the number of moles and Liters into the equation Molarity=2.14 mol/1L Molarity=2.14 So, the molarity is 2.14 M
The molarity is 0,031.
The concentration of a solution can be expressed in many ways. One of them is as the molarity of the solution. A solution with molarity equal to one has one mole of the solute dissolved in every liter of the solutions
Because you have 6.68 moles of Li2SO4 and 2.500 liters of water, the overall molarity of your solution is 2.67 M.
0.27 M
Start by looking up atomic masses of Na, N and O. Convert grams to kilograms.
Get moles silver nitrate. 255 grams AgNO3 (1 mole AgNO3/169.91 grams) = 1.5008 moles AgCO3 --------------------------------Now; Molarity = moles of solute/Liters of solution ( 1500 ml = 1.5 Liters ) Molarity = 1.5008 moles AgNO3/1.5 Liters = 1.00 M AgNO3 ---------------------
Need moles aluminum oxide first. 51 grams Al2O3 (1 mole Al2O3/101.96 grams) = 0.5002 moles Al2O3 ======================Now, Molarity = moles of solute/Liters of solution (500 ml = 0.500 Liters ) Molarity =0.5002 moles Al2O3/0.500 Liters = 1.0 M Al2O3 solution ----------------------------
Molarity = moles of solute/liters of solution 2500 milliliters = 2.5 liters ------------------------------------ 12.2 grams SrCl2 (1 mole SrCl2/158.52 grams) = 0.07696 moles strontium chloride -------------------------------------------------------------------------------------------------------- so, Molarity = 0.07696 moles SrCl2/2.5 liters = 3.07 X 10 -2 M SrCl2 -------------------------------------
first determine the number ofmoles dissolved in given solution then .5 moles moles dissolved in 800g. as comparison with 1000g of water, we know 100g of water dissolve only.1 moles of a glucose so we .7moles of glucose dissolve in 800g.
The molarity is 2,973.
If 1,1 is grams the molarity is 0,317.
31 grams HCl (1mol/36.458g ) = 0.850 moles 500cm^3 = 0.50 Liters Molarity = moles of solute/liters of solution Molarity = 0.850mol/0.50L = 1.7 Molarity