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0.063 g of oxalic acid * (1 mol H2C204*2H2O / 126.07 g) = 0.0004997 mol H2C2O4*2H2O 0.0004997 mol H2C204 / 0.250 L = 0.001999 M of H2C2O4

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15y ago
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14y ago

molar mass H2C2O4 = 2*1 + 2*12 + 4*16 = 90.0 g/mol = 90.0 mg/mmol

25.5 mg in 1.0 ml = 25.5/90.0 mmol/ml = 0.283 mmol/ml = 0.283 mol/L = molarity oxalic acid

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11y ago

.0056 M

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Q: If 25.5mg of oxalic acid dihydrate are dissolved in 1.00 ml of solution what is the molarity of the resulting solution?
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