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If 8 women are pregnant what is the probability that there will be 4 boys and what is the probability that at least 7 girls will be born?
Wiki User
∙ 14y ago
Assuming that the probability of 1 woman have a boy is .5
Binomial Distribution can be used to solve the problem.
b(k;n,p)
= (n choose k) p^k * (1-p)^(n-k)
k= number of boys
n= number of trials
p= probability of boy
Assume p is equal to probability of having a boy
First question we are looking for four boys. ie k=4
n = 10
=(10 choose 4) 0.5^4 * (1-.5)^4
= 0.8203
Question 2)
At least 7 girls means 1 boy or 0 boys will be born
Case 1) 0 boys born
Use binomial
(10 choose 0) 0.5^0 * (1-.5)^8
= 0.00390625
Case 2) 1 boy born
(10 choose 1) 0.5^1 * (0.5)^7
=0.0390625
Case 1 + Case 2= 0.04296875 Probability of at least 7 girls
Wiki User
∙ 14y ago
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