The equation is as follows:
0.9(1) + 0.6(40) = 0.67x
To solve we simplify:
24.9 = 0.67x
Then Divide:
24.9/0.67 = x
The Answer: 37 liters
Yes, you can.
900 ounces. Since this contains 20% copper, The copper content will be 180 ounces. The original 300 ounces contain 30% copper which is also 180 ounces. Hence in the resulting mixture of 1200 ounces (300+900), the total copper is 360 ounces (180+180). Hence the copper content of resulting mixture is 360/1200 which is 30%
C3 h3o
Sucrose ~ 93.81%
Divide the percent by 100 and then simplify the resulting fraction.
note: NOT percent composition.
Yes, you can.
Percent composition can be used to calculate the percentage of an element/compound in a mixture. From the percent composition, you can also find the empirical formula. And from the empirical formula you can find the actual molecular weight.
Mercury's internal composition is made up of 70 percent metals and 30 percent silicate. The core is a hot, liquid iron-nickel mixture.
Type your answer here... / 2/5,1/3,3/10 arrange the ascending order
Mercury's internal composition is made up of 70 percent metals and 30 percent silicate. The core is a hot, liquid iron-nickel mixture.
the mixture composition is 12% that means in 100 ml of solution 12 ml is alcohol and when u are taking of 12 ml of alcohol then rest i.e. 88 ml is water
The percent composition of lithium in LiOH is: 29,21 %.
Can you be more specific? Percent composition is usually the percent of an element in a compound.
Percent composition is usually expressed as a percent by mass, but in the case of gases and vapors, it is often expressed as a percent by volume.
You can use percent composition to see how much much flour contributes to the mass of an overall cake. You can see how much kool aid powder is in a given amount of kool aid drink, in percentage. Percentage composition can be used for virtually anything that has a mixture of things. So you don't always have to think percentage composition refers to chemical compounds, such as H2O or KMnO4.
mary mixed 2l of an 80% acid solution with 6l of a 20% acid solution. what was the percent of acid in the resulting mixture