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What is the radius of a circle and its centre that passes through the points of 5 0 and 3 4 and -5 0 on the Cartesian plane?
Points: (5, 0) and (3, 4) and (-5, 0) Equation works out as: x^2+y^2 = 25 Radius: 5 units in length Centre of circle is at the point of origin (0, 0) on the Cartesian plane.
What is the length of the tangent line from the coordinate of 9 0 to a point where it touches the circle of x2 plus 8x plus y2 -9 equals 0?
Circle equation: x^2 +8x +y^2 -9 = 0 Completing the square: (x+4)^2 +y^2 = 25 Center of circle: (-4, 0) Radius of circle: 5 Distance from (-4, 0) to (9, 0) = 13 which will be the hypotenuse of a right triangle Length of tangent line using Pythagoras; theorem: 13^2 -5^2 = 144 Therefore length of tangent line is the square root of 144 = 12 units
What is the length of 3 0 0 -6?
Distance between (3, 0) and (0, -6) = sqrt[(3 - 0)2 + (0 - -6)2] = sqrt(32 + 62) = sqrt(45) = 3*sqrt(5) or 6.71 approx.
What is the length of the line x -y equals 10 that spans the curve x squared plus y squared plus 4x plus 6y -40 equals 0 showing work?
If: x^2+y^2+4x+6y-40 = 0 and x-y =10 or as x = 10+y Then: (10+y)^2+y^2+4(10+y)+6y-40 = 0 Thus: 100+20y+y^2+y^2+40+4y+6y-40 = 0 Collecting like terms: 2y^2+30y+100 = 0 or as y^2+15y+50 = 0 When factored: (y+5)(y+10) = 0 So: y = -5 or y = -10 By substitution equations intersect at: (0, -10) and (5, -5) Length of line is the square root of: (5-0)^2 plus (-5--10)^2 = square root of 50 Therefore length of line is: square root of 50 or about 7.071 to three decimal places
Is 2/5 closer to 1 or 0?
2/5 is closer to 0.
What is the length of the line segment that connects points 0 0 and 2 4?
√[(2 - 0)2 + (4 - 0)2] = √(4 + 16) = √20 ≈ 4.5 or √20 = √(4 x 5) = 2√5
The circumference of a circle is 31.40 inches find approximate length of the circle's radius?
The approximate radius is five (5) inches.
What is the radius of a circle and its centre that passes through the points of 5 0 and 3 4 and -5 0 on the Cartesian plane?
Points: (5, 0) and (3, 4) and (-5, 0) Equation works out as: x^2+y^2 = 25 Radius: 5 units in length Centre of circle is at the point of origin (0, 0) on the Cartesian plane.
What is the length of the tangent line from the coordinate of 9 0 to a point where it touches the circle of x2 plus 8x plus y2 -9 equals 0?
Circle equation: x^2 +8x +y^2 -9 = 0 Completing the square: (x+4)^2 +y^2 = 25 Center of circle: (-4, 0) Radius of circle: 5 Distance from (-4, 0) to (9, 0) = 13 which will be the hypotenuse of a right triangle Length of tangent line using Pythagoras; theorem: 13^2 -5^2 = 144 Therefore length of tangent line is the square root of 144 = 12 units
What is the length of 3 0 0 -6?
Distance between (3, 0) and (0, -6) = sqrt[(3 - 0)2 + (0 - -6)2] = sqrt(32 + 62) = sqrt(45) = 3*sqrt(5) or 6.71 approx.
What is the length of the line from 7 5 which is perpendicular to the line of 3x plus 4y minus 16 equals 0?
Equation of (7, 5) = 4x-3y-13 = 0 Intersection of the straight line equations = (4, 1) Length of line is the square root of the sum of (7-4)2+(5-1)2 =25 Therefore: length of the line from (7, 5) perpendicular to 3x+4y-16 is 5 units
What is the perpendicular line length from coodinates of 7 and 5 to the straight line equation 3x plus 4y -16 equals 0 showing work?
1 Point of origin: (7, 5) 2 Equation: 3x+4y-16 = 0 3 Perpendicular equation: 4x-3y-13 = 0 4 Both equations intersect at: (4, 1) 5 Line length is the square root of: (7-4)2+(5-1)2 = 5
What is the most reasonable estimate of the length of a car?
About 5 meters (16.4 feet) would be a good estimate of a car length. That's the approximate length of a large family car.
What is the length of the line x -y equals 10 that spans the curve x squared plus y squared plus 4x plus 6y -40 equals 0 showing work?
If: x^2+y^2+4x+6y-40 = 0 and x-y =10 or as x = 10+y Then: (10+y)^2+y^2+4(10+y)+6y-40 = 0 Thus: 100+20y+y^2+y^2+40+4y+6y-40 = 0 Collecting like terms: 2y^2+30y+100 = 0 or as y^2+15y+50 = 0 When factored: (y+5)(y+10) = 0 So: y = -5 or y = -10 By substitution equations intersect at: (0, -10) and (5, -5) Length of line is the square root of: (5-0)^2 plus (-5--10)^2 = square root of 50 Therefore length of line is: square root of 50 or about 7.071 to three decimal places
How do you play burning hell by tom Jones on guitar?
Tom Jones - BURNING HELL Standard Tuning CAPO 2 Intro/Main Riff/Verse |------------------------------| |------------------------------| |-9\---------------------------| |-9\-------------5--2-----2----| |-----2-4-2-2-2--2--2--5--2----| |-----0-0-0-0-0--0--0--0--0----| Sometimes it's this without the first hit |--------------------------| |--------------------------| |--------------------------| |------------5--2-----2----| |---4-2-2-2--2--2--5--2----| |---0-0-0-0--0--0--0--0----| Chorus(?) |-------------------------| |-------------------------| |-------------------------| |-------------------------| |--5--7--9--12--14/12\14--| |--3--5--7--10--12/10\12--| |--------------------------------------------------------------| |--------------------------------------------------------------| |--------------------------------------------------------------| |-------------------------------2-2-4-2-5--2-2-2--2-2-4-2-5----| |--5-5-7-5-8--5-5-5--5-5-7-5-8--0-0-0-0-0--0-0-0--0-0-0-0-0----| |--3-3-3-3-3--3-3-3--3-3-3-3-3---------------------------------| That's about it. Just throw in a couple of slides up to the 9th fret like at the very beginning of the song and you're good to go!!
Length of a rectange is 5m greater than the width the perimeter is 84m2 what is the length and width?
Rectangular perimeter = 2(Length + Width) Width = a Length = a+5 Then, 84 = 2(a+a+5) 42 = 2a+5 (42-5)/2 = a = 18.5m = Width Length = a+5 = 23.5m
Is 2/5 closer to 1 or 0?
2/5 is closer to 0.
