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If A gas is at 0 degrees C and occupies 6.8 liters and the temp is raised to 20 degrees C what is the new volume?
Wiki User
∙ 14y ago
Please reference your Chem 101 textbook for the Ideal Gas Law:
pV = nRT
From there you can derive the proper Isobaric Process calculation:
V2 =V1(T2/T1)
Your given are:
V1 = 6.8 L
T2 = 20 ºC
T1 = 0 ºC
But since you cannot divide by Zero, you'd leave it at multiplying 6.8 by 20.
V2 = 136 L
Wiki User
∙ 14y ago
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