The sum of the four angles is 360 degrees. Three of the angles add up to 310 so the fourth must be 360 - 310 = 50 degrees.
If those are the angles of a quadrilateral then the 4th angle is 360-100-80-100 = 80 degrees
80 degree
125 degrees
No because the 4 interior angles of a quadrilateral add up to 360 degrees
A trapazoid has those angles
If those are the angles of a quadrilateral then the 4th angle is 360-100-80-100 = 80 degrees
50 degrees (360 degrees in a quadrilateral)
125°
4
80 degree
It is 100 degrees.
125 degrees
No because the 4 interior angles of a quadrilateral add up to 360 degrees
A trapazoid has those angles
Yes as for example a square has 4 interior equal angles of 90 degrees.
It is a parallelogram or a rhombus
The sum of the angles in a trapezoid is 360 degrees, therefore, the forth angle in this problem is: 360 - (60+120+80) = 100 degrees