I assume that points BC is a straight line and that D is the point where the line DE intersects BC. If this is so, and CDE is 55 degress, then BDE is 125 degrees.
cos(125) = cos(180 - 55) = cos(180)*cos(55) + sin(180)*sin(55) = -cos(55) since cos(180) = -1, and sin(180) = 0 So A = 55 degrees.
-305 degrees would be equal to 55 degrees, which can be found in quadrant one in the standard position.
30 degrees.
55 degrees.
33 degrees Kelvin converts to -240.15 degrees Celsius; 55 degrees Kelvin converts to -218.15 degrees Celsius.
55 degrees Celsius = 131 degrees Fahrenheit131 degrees F
131
cos(125) = cos(180 - 55) = cos(180)*cos(55) + sin(180)*sin(55) = -cos(55) since cos(180) = -1, and sin(180) = 0 So A = 55 degrees.
A parallelogram or a rhombus would fit the given description because they both have equal opposite obtuse angles and equal opposite acute angle that all add up to 360 degrees.
55º Fahrenheit = 12,77º Celsius. 1ºCelsius = 33,8º Fahrenheit.
-305 degrees would be equal to 55 degrees, which can be found in quadrant one in the standard position.
The angle of incidence is ALWAYS equal to the angle of reflection, therefore the degree of the angle reflection is 55 degrees.
The melting point of oxygen is - 218 degrees Celsius. That is equal to 55. 1 Kelvin or - 360 degrees Fahrenheit.
The complement of 35 degrees is 55 degrees, since they add up to 90 degrees.
cos(35)sin(55)+sin(35)cos(55) If we rewrite this switching the first and second terms we get: sin(35)cos(55)+cos(35)sin(55) which is a more common form of the sin sum and difference formulas. Thus this is equal to sin(90) and sin(90)=1
The answer is -218.15 C (approx.). The Kelvin scale starts at absolute zero and is used in scientific laboratories. Celsius is for general use and set 0 and 100 as melting and boiling point of water respectively. To convert from K to C, subtract 273.15 from K.
55 degrees Fahrenheit is 12.78 degrees Celsius.