I assume that points BC is a straight line and that D is the point where the line DE intersects BC. If this is so, and CDE is 55 degress, then BDE is 125 degrees.
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cos(125) = cos(180 - 55) = cos(180)*cos(55) + sin(180)*sin(55) = -cos(55) since cos(180) = -1, and sin(180) = 0 So A = 55 degrees.
-305 degrees would be equal to 55 degrees, which can be found in quadrant one in the standard position.
30 degrees.
55 degrees.
33 degrees Kelvin converts to -240.15 degrees Celsius; 55 degrees Kelvin converts to -218.15 degrees Celsius.