I assume that points BC is a straight line and that D is the point where the line DE intersects BC. If this is so, and CDE is 55 degress, then BDE is 125 degrees.
cos(125) = cos(180 - 55) = cos(180)*cos(55) + sin(180)*sin(55) = -cos(55) since cos(180) = -1, and sin(180) = 0 So A = 55 degrees.
-305 degrees would be equal to 55 degrees, which can be found in quadrant one in the standard position.
30 degrees.
55 degrees.
33 degrees Kelvin converts to -240.15 degrees Celsius; 55 degrees Kelvin converts to -218.15 degrees Celsius.
-55 degrees Celsius is equal to -67 degrees Fahrenheit.
-55 degrees Celsius is equal to -67 degrees Fahrenheit.
55 degrees Celsius is equal to 131 degrees Fahrenheit.
55 degrees Celsius is equal to 131 degrees Fahrenheit.
55º Fahrenheit = 12,77º Celsius. 1ºCelsius = 33,8º Fahrenheit.
55 degrees Celsius is equal to 131 degrees Fahrenheit.
-55 degrees Celsius = -67 degrees Fahrenheit.
Negative 55 degrees Celsius is equal to -67 degrees Fahrenheit.
55 degrees Celsius is equal to 131 degrees Fahrenheit. This conversion can be calculated using the formula: (°C x 9/5) + 32 = °F.
cos(125) = cos(180 - 55) = cos(180)*cos(55) + sin(180)*sin(55) = -cos(55) since cos(180) = -1, and sin(180) = 0 So A = 55 degrees.
55 degrees Celsius is equal to 131 degrees Fahrenheit.
A parallelogram or a rhombus would fit the given description because they both have equal opposite obtuse angles and equal opposite acute angle that all add up to 360 degrees.