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If John is 8 and his father is 42 years old how many years later will John's father be 3 times as old as John?
Wiki User
∙ 13y ago
Nine years later, John will be 17 and his father will be 51.
17x3=51
Wiki User
∙ 13y ago
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The age of the father 6 years ago is four times then the age of his son The age of the father 4 years hence is double the then age of his son?
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The father is always 28 years older than his son so the equation can be written: (1) father = son + 28 at all times after birth at some point father is three times older than son so: (2) father = 3son So we can combine (1) and (2) equations as: 3son = son + 28 2son = 28 son = 14 so when the son is 14 the father is 28 years older which is 42 and 3 times older than 14.
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The age of the father 6 years ago is four times then the age of his son The age of the father 4 years hence is double the then age of his son?
The son is 11, the father is 26
A father is 32 years old His son is 4 In how many years will the father be three times as old as his son What is the algerbraic equation for that?
The father is always 28 years older than his son so the equation can be written: (1) father = son + 28 at all times after birth at some point father is three times older than son so: (2) father = 3son So we can combine (1) and (2) equations as: 3son = son + 28 2son = 28 son = 14 so when the son is 14 the father is 28 years older which is 42 and 3 times older than 14.
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