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The father is always 28 years older than his son so the equation can be written: (1) father = son + 28 at all times after birth at some point father is three times older than son so: (2) father = 3son

So we can combine (1) and (2) equations as: 3son = son + 28

2son = 28

son = 14 so when the son is 14 the father is 28 years older which is 42 and 3 times older than 14.

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Q: A father is 32 years old His son is 4 In how many years will the father be three times as old as his son What is the algerbraic equation for that?
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