Assume the die is fair. What are the numbers on the four sides? How many times are you allowed to roll it? If the four numbers are 1,2,3 and 4 and you want the first three rolls to be 1,3,2 in that order, the probability is 1/4*1/4*1/4 = 1/64.
Assuming you are talking about fair, six-sided dice, then the probability of rolling a 1 on the first roll in 1/6, and the probability of rolling a 2 on the second roll is 1/6. Putting these together, the probability of rolling 1 on the first die and 2 on the second die is 1/36. If you do not care about the order, then you could roll 1,2 or 2,1; in this case the probability would be 2/36, or 1/18.
The probability of getting an odd number when you roll one die is 1 in 2. In order to get an odd sum with two dice, one of them has to be odd and one of them has to be even. The probability of rolling an odd sum is still 1 in 2, since each die is unrelated in probability to the other.
In order to answer, the number of questions on the test must be given.
The answer depends on whether or not order is important: If you want a 4 first, then a 1, the probability is (1/6) x (1/6) = (1/36) =~ 0.028. If you don't care whether the four or the one comes first, then the probability is 2 * (1/36) =~ 0.056.
The probability of a phone being answered in 2 minutes, given that the average time is 3 minutes, is not specified in the information given. More details or specific probabilities are needed to determine the answer.
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52 in all cases, the overall probability is 0.0624.
Yes, you divide the number of expected outcomes by the number of possible outcomes in order to determine probability.
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If all parties were given notice of the hearing and none asked for a continuance or postponement then the court will continue with the hearing.
To work this out, you first need to calculate the probability of the first 8 passing, and the final 2 failing. That is 97%8x3%2 which equals 0.070536902349392649% The next step is to find out how many different ways the people can be ordered. We have 10 in total and want to order 8, so the number is 10C8, which is 45. Multiply this by the above probability and you get 3.174160605722669205% Thus the probability that 8 of the next 10 will pass is 3.17%
Replacement parts for the Top-o-Matic cigarette rolling machine can be ordered from American Thrust Tobacco, LLC. The parts are listed in a diagram so you can order the exact part you need to repair your rolling machine.
This question is extremely poorly phrased. The probability of three boys [sitting] in a row at an all boys school is 1. At an all girls school it is 0 and is otherwise somewhere in between. If the question is about birth order, do you take account of the fact that nearly half the families have two or fewer children? So that in half the cases the probability is 0. Finally, children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability of giving birth to three boys in a row is 0.523 = 0.1381