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If a ball is thrown into the air with a velocity of 38 ft per sec its height in feet after t seconds is given by y equals 38t minus 16t2 Find the velocity when t equals 2?
Eclipse87
Substitute the 2 in for t.
38(2)-16(2)^2
76-64=12
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∙ 14y ago
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If a ball is thrown vertically up with the velocity of 40m s what would be its velocity after two seconds?
Ignoring air resistance and using g = 9.81 ms-2, velocity = 20.38 ms-1.
The height h of a ball thrown into the air with an initial vertical velocity of 48 feet per second from a height of 5 feet above the ground is given by the equation?
At any time 't' seconds after the ball is released,until it hits the ground,h = 5 + 48 t - 16.1 t2
A rock is thrown from a cliff and hits the ground 5 seconds later at a distance of 50 meters from the cliff How high was the cliff?
Assuming you throw the rock horizontally off the cliff it drops down at the acceletrtion of gravity. height= 1/2 gt^2 With g = 9.8 m/sec and t = 5 seconds we have height = (1/2) (9.8)(5)(5) = 122.5 meters notice it has nothing todo with the 50 meter distance, which depends on the horizontal velocity.
How can you used trigonometry in projectile motions?
when a body is thrown at an angle in a projectile motion, the vertical component of the velocity is vcos(B) ..where v is the velocity at which the body is thrown and B represents the angle at which it is thrown.Similarly horizontal component is vsin(B). these components are useful in determining the range of the projectile ,the maximum height reached,time of ascent,time of descent etc.,
Is the total time of a ball thrown upwards is it equal to the total time of the downward velocity?
There's no such thing as "time of the downward velocity", but I think I get the sense of your question. If the effects of air resistance can be disregarded, then any object thrown upwards spends half of its time rising, and the identical amount of time falling back to the height of your hand when you let it go.
What is tje velocity of a ball thrown upward at 16 ft/sec?
If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t - 16t^2. If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t − 16t^2.
What is the velocity of a ball thrown 20 ft in 4 seconds?
In the case of constant velocity (or speed), velocity = distance / time.
A ball thrown vertically upward returns to the starting point in 8 seconds.find its initial velocity.?
A ball thrown vertically upward returns to the starting point in 8 seconds.-- Its velocity was upward for 4 seconds and downward for the other 4 seconds.-- Its velocity was zero at the turning point, exactly 4 seconds after leaving the hand.-- During the first 4 seconds, gravitational acceleration reduced the magnitude of its upward velocity by(9.8 meters/second2) x (4 seconds) = 39.2 meters per second-- So that had to be the magnitude of its initial upward velocity.
The velocity of a body thrown vertically upward is reduced into half in one secondwhat is the maximum height attained by it?
velocity is found by dividing the distance with time. In a second the height traveled is found by multiplying the velocity by the time taken and then dividing the answer by two.
What height is reached by a 4.0kg ball that is thrown vertically up into the air with an initial velocity of 8.5ms1 if by the time it is height (h) metres above the starting point it has a velocity of?
Height reached = 3.7 metres.The mass of the ball is not really relevant.
When will a stone return to the groun if it is thrown upward with an initial velocity of 16ms?
After just over three and a quarter seconds.
What is displacement if a ball is thrown up with certain velocity it attains maximum height and comes back to the thrower?
Zero
A ball is thrown with enough speed straight up so that it is in the air several seconds What is the velocity of the ball when it gets to its highest point?
A the highest point its velocity will be zero.
If a ball is thrown vertically up with the velocity of 40m s what would be its velocity after two seconds?
Ignoring air resistance and using g = 9.81 ms-2, velocity = 20.38 ms-1.
The height h of a ball thrown into the air with an initial vertical velocity of 48 feet per second from a height of 5 feet above the ground is given by the equation?
At any time 't' seconds after the ball is released,until it hits the ground,h = 5 + 48 t - 16.1 t2
A rock is dropped from the top of a cliff what is the velocity after 2 seconds 5 seconds 10 seconds?
Since the equation for time=sqrt(2h/g) set 2 seconds for time and 9.8 for gravity so 2=sqrt(2h/9.8) clear the sqrt by squaring both sides 4= 2h/9.8 9.8*4 =2h (9.8*4)/2 = height. now that you have the height, you can do v=distance/time v=height from the equation prior/2 seconds i hope that works..
What happens when two objects of different mass is thrown up. which will reach maximum height if both are thrown with same velocity?
If you ignore air resistance, then they will reach their maximum height at the same time. In order not to ignore air resistance, you would need to know their shapes.
