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If a boat travels due East for a distance of 15 miles then it travels due North for a distance of 20 miles at which point it drops anchor then how many miles is the boat from its starting point?
Wiki User
∙ 14y ago
This is a question based on Pythagoras.
The answer is sqrt[(15)2 + (20)2] = 25 miles
Wiki User
∙ 14y ago
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A boat travels due east for a distance of 15 miles it travels due north for a distance of 20 miles at which point it drops anchor how many milesis the boat from it?
A trick question! The boat is still quite close to the point where it dropped the anchor! ============================ The boat is approximately 25 miles from its starting point, and exactly zero miles from the point where the anchor was dropped.
A boat travels due east for a distance of 15 miles It then travel due north for a distance of 20 miles at which point it drops anchor How many miles is the boat far from it's starting point?
25 miles
A boat travels due East for a distance of 15miles it then travels due North for a distance of 20miles at which point it drops anchor how many miles is the boat from its statring point?
25 miles
A boat travels due east for a distance of 15 miles its then travels due north for a distance of 20 miles at which point it drops anchor how many miles is the boat from it's starting point?
This is where you apply the pythagorean theorem: d = √(152 + 202) ∴d = √(225 + 400) ∴d = √(625) ∴d = 25 So the boat is 15 miles from it's starting point
A boat travels due east for a distance of 15 miles. It then travels due north for distace of 20 miles. How many miles is the boat from it's starting point?
25 miles.
A boat travels due east for a distance of 15 miles it then travels due north for a distance of 20 miles at which point it drops anchor How many miles is the boat from its starting point?
hm
A boat travels due east for a distance of 15 miles it travels due north for a distance of 20 miles at which point it drops anchor how many milesis the boat from it's starting point?
25
A boat travels due east for a distance of 15 miles it travels due north for a distance of 20 miles at which point it drops anchor how many milesis the boat from it?
A trick question! The boat is still quite close to the point where it dropped the anchor! ============================ The boat is approximately 25 miles from its starting point, and exactly zero miles from the point where the anchor was dropped.
A boat travels due east for a distance of 15 miles It then travel due north for a distance of 20 miles at which point it drops anchor How many miles is the boat far from it's starting point?
25 miles
A boat travels due East for a distance of 15miles it then travels due North for a distance of 20miles at which point it drops anchor how many miles is the boat from its statring point?
25 miles
A boat travels due east for a distance of 15 miles it then travels due north for a distance of 20 miles at which point it drops anchor how many miles is the boat from its stsring point?
5 miles
A boat travels due east for a distance of 15 miles its then travels due north for a distance of 20 miles at which point it drops anchor how many miles is the boat from it's starting point?
This is where you apply the pythagorean theorem: d = √(152 + 202) ∴d = √(225 + 400) ∴d = √(625) ∴d = 25 So the boat is 15 miles from it's starting point
Fred will be four blocks from his starting place if he travels two blocks north then three blocks east and then two blocks south.?
That is incorrect. The distance travelled north cancels out the distance travelled south. Therefore - he only travels three blocks east.
A boat travels due east for a distance of 15 miles. It then travels due north for distace of 20 miles. How many miles is the boat from it's starting point?
25 miles.
A boat travels due east for a distance of 15 miles It then travel due north for a distance of 20 miles at which point it drops anchor How many miles the boat travels from is starting point?
you have to use quadratcic equation= A2 + B2 = C2 152 + 202 = C2 625= C2 C= 25 you have to use quadratcic equation= A2 + B2 = C2 152 + 202 = C2 625= C2 C= 25
A boat travels due east for a distant of 15 miles it then travel due north for a distant of 20 miles at which point it drops anchor how many miles is the boat from its starting point?
25 miles
What is the velocity of amissile tha travels north 8000 meters in 10.12 seconds?
Velocity = 790.514 m/s North (rounded)The idea is to divide the distance by the time.
