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heres the average 2.2 seconds
900 m/s velocity=meters/sec v=4500/5=900
666.67 seconds
Average Velocity = change in position/change in time V = 35.2 m - 0 m/6.7 s - 0 s 4.8 m/s
a high speed train travels south for 2.00 h for a distance of 454km. what is its average velocity?
heres the average 2.2 seconds
3.00 m/s
900 m/s velocity=meters/sec v=4500/5=900
7.5
666.67 seconds
4 m/s
Average Velocity = change in position/change in time V = 35.2 m - 0 m/6.7 s - 0 s 4.8 m/s
a high speed train travels south for 2.00 h for a distance of 454km. what is its average velocity?
The person travels a total of 4000 m in 400 seconds, so their average speed is 10m/s. However velocity is a vector quantity, and is defined as displacement/time. The total displacement is only 400 m, so the average velocity is just 1m/s.
All you need to know is the distance the marble travelled and how long it took to travel that distance. For example, if a marble travels 30 cm in 5 seconds then its average velocity would be 30 / 5 cm / sec = 6 cm / sec.
Average velocity is total distance by total time . let us calculate velocity at the end of 6 seconds. v=vo+at v= 0+1.7*6 v=10.2 m/sec distance travelled by object in six seconds x= vot+1/2at2 x=0+.5(1.7)(62) x=30.6 m the final velocity at the end of six seconds that is 10.2m/s will be the initial velocity when objects moves with uniform velocity with a constant velocity x= vot+1/2at2 . . . accel is 0 since velocity is constant between 6 & 15 secs. x=10.2*9=91.8 Again . . average velocity is total distance by total time. Average velocity= [30.6+91.8]/15= 122.4*15 = 8.16m/s
First you need to find the two different speeds of the car which is the distance/time. We find that the car first travels at an average of 6ms-1 and then after accelerating has a speed of 10ms-1. Acceleration is the rate of change of velocity over time, our change of velocity being 10-6=4ms-1 and the change in time being stated as 3 seconds we can convert this into... (4/3)ms-2