Velocity = distance / time
Given d = 72 miles ; t = 4 hour
V = 72 miles / 4 hour
= 18 miles per hour
1/18
W/4 mph
Ok, SO if the cyclist travels 12 km/h and he travels for 5 hours, 12 x 5 is 60 so 60 kilometers.
Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking? A. 2 hoursB. 4 ½ hoursC. 5 ¾ hoursD. 6 hoursE. 7 ½ hours AnswerThe distance the 1st cyclist travels is 6(3+t) miles, andthe distance the 2nd cyclist travles is 10t miles...where t=the number of hours since cyclist #2 starts.Now solve: 6(3+t)=10t ==> 18+6t=10t ==> 18=4t ==> t=4.5 hrs==> 4.5 hours = 4 hrs 30 minutes
1 and a half hours
1/18
W/4 mph
Ok, SO if the cyclist travels 12 km/h and he travels for 5 hours, 12 x 5 is 60 so 60 kilometers.
Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking? A. 2 hoursB. 4 ½ hoursC. 5 ¾ hoursD. 6 hoursE. 7 ½ hours AnswerThe distance the 1st cyclist travels is 6(3+t) miles, andthe distance the 2nd cyclist travles is 10t miles...where t=the number of hours since cyclist #2 starts.Now solve: 6(3+t)=10t ==> 18+6t=10t ==> 18=4t ==> t=4.5 hrs==> 4.5 hours = 4 hrs 30 minutes
ANSWER # 1 It looks like cyclist #2 is out to catch cyclist #1. Our #2 cyclist is starting out 3 hours later than cyclist #1, and is traveling at 10 mph versus the 6 mph of cyclist #1. There are a couple of ways to solve this one, so there is no "right way" to do it. Opting for an easy one, let's think of it this way. Think of it like both cyclists are going the same speed, the 6 mph. Yes, our trailing cyclist can't ever catch the lead cyclist, but this is a short cut, okay? If both cyclists ride, the space between them neither increases or decreases. Here's the scoop. It's the space between them that we're gonna look at. That space is 3 hours long. Here's the thinking. Cyclist #2 is going faster than #1 by 4 mph, and that is the "extra" speed that our #2 cyclist is using to close the gap, to make up that 3 hours. If cyclist #2 is going to make up 3 hours at 4 mph (the differential speed), how much ground is he going to have to make up? Well, cyclist #1 is riding at 6 mph for 3 hours to create the gap. That's 6 time 3 or 18 miles that cyclist #2 is going to have to make up. And our #2 guy is going to have to make up the 18 miles at 4 mph (the differential speed). How long is it going to take him? The 18 miles divided by 4 mph equals 4 ½ hours. Presto. It will take our #2 cyclist that 4 ½ hours to catch up to cyclist #1. If we want to check our work, take cyclist #2's 10 mph speed and multiply by 4 ½ hours and we'll see that he has to ride 45 miles to catch cyclist #1. Let's see what happens for cyclist #1. This cyclist will be riding for 4 ½ hours plus the 3 hour head start. That's 7 ½ hours of riding at 6 mph. The 7 ½ times 6 equals 45 miles. Check! We're good here! ANSWER # 2 1st = 6(x +3) ......... 2nd = 10x 10x = 6(x+3) x = 4 (1/2)
1 and a half hours
The duration of Death of a Cyclist is 1.47 hours.
Answer:3 1/3 hours or 3 hours and 20 minutesSolution:distance = velocity x timethe distance travelled by the first cyclist = 15 x timethe distance travelled by the second cyclist = 12 x timethe difference distance = 15 x time - 12 x timethis difference will be 10 miles when15 x time - 12 x time = 103 x time = 10time = 10/3 = 3 1/3 hours= 3 hours and 20 minutes.
17.14286 km. hr. is the avg. speed
8 hours for me to commute to work per week.
About 9 hours if the average speed is 55.
To get the average speed, divide distance by time.